BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Absolute value

Expert replies
by Uri » Wed May 06, 2009 6:08 am
Is |x-z|>|x-y|?
1) |z|>|y|
2) 0>x

OA: [spoiler](E)[/spoiler]

What is the best way to attack this type of problem, where the absolute value is considered in both the sides? I find that picking numbers is very much time-consuming. Is there any other way out?
Join the discussion
Source: — Data Sufficiency |

Re: Absolute value

by Brent@GMATPrepNow » Wed May 06, 2009 8:36 am
Uri wrote:Is |x-z|>|x-y|?
1) |z|>|y|
2) 0>x

OA: [spoiler](E)[/spoiler]

What is the best way to attack this type of problem, where the absolute value is considered in both the sides? I find that picking numbers is very much time-consuming. Is there any other way out?
One thing that's important to recognize is that |k| is the distance from k to 0 on the number line.
Similarly, |x-z| gives us the distance between x and z on the number line and |x-y| gives us the distance between x and y on the number line.

So, the question can be reworded as "On the number line, is z further away from x than y is?"
From here, you can use the number line and try different values of x, y, and z to determine the answer. Using the number line approach, will give you a nice visual to work with.
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by Uri » Thu May 07, 2009 4:52 am
thanks for the valuable suggestion, brent!
following your advice, i have worked out the problem in the below-mentioned way. hope i have applied your suggestion correctly!


The question asks, “Is z further from x than y is from x?”
St 1: Until we know the position of x, we can not say for sure which one is nearer to x. Consider three numbers. We know that one number is greater than the other. But if we don’t know the position of the third number, we can not be certain which of these two numbers will be nearer to the third one. So, this statement is insufficient.
St 2: We know that x is negative. But if we don’t know the position of the other two numbers, we can not be sure which one is nearer to x.
Consider St 1 and St 2 together. We know that z is further from zero than y is from zero. We also know that x is negative. Now if both y and z are negative, then z must be further than x, but if z is negative and y is positive, then depending on the value of x, any one of y or z can be nearer to x. Thus both the statements together are also not sufficient.
Join the discussion