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Absolute value--> DS question

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by beatthegmatinsept » Fri Sep 17, 2010 9:01 am
haisuresh wrote:Its a DS question

is |x| > |y| ?

1. x^2 > y^2
2. x > y
IMO A.
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by haisuresh » Fri Sep 17, 2010 9:23 am
How ?
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by beatthegmatinsept » Fri Sep 17, 2010 9:29 am
haisuresh wrote:Its a DS question

is |x| > |y| ?

1. x^2 > y^2
2. x > y
(a) Since absolute value of any number is always positive, so is the square of any number. So if the square of x is greater than square of y, then |x| must be > |y|.
(For a quick check, you can take a couple different values of x and y and look for same results).
Sufficient.

(b) x > y
Should be fine when both x and y are positive.
But if y is negative,
e.g. x = 3, y = -4, then x > y.
BUT we are talking absolute values here,
so |3| is NOT > |-4|.
Insufficient.

Whats the OA?
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by haisuresh » Fri Sep 17, 2010 9:36 am
OA : A
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