a sum

5 is my answer to ur first question.

yes it is. can you explain me how u got there?

My Answer is 5.

m+ n = Z+4
n = e + y

m + n = z + 4 + e + y
4 + y = -5
y = -9

e + z = 10

m + n = y + (e + z) + 4

m + n = -9 + (10) + 4

m + n = 5

Hope this is clear

yes it is, thanks!

i didn t get the format!

I didn't understsnd the format either. Can anyone please explain?

1st question: Solution is

X+ 4 = 1
So X=-3
Y+4 = -5
So y = -9,
m= z+4,
e+z = 10,
e+y = n,
x+f = 2,
So f= 5
z+f = 5
So z= 0
so m= 4,
x+e = 7,
So e = 10
M + n = z+4+e+y = 0+4+10-9 = 5



2nd question:
question is same as 1st.

sudhir3127 wrote:My Answer is 5.

m+ n = Z+4
n = e + y

m + n = z + 4 + e + y
4 + y = -5
y = -9

e + z = 10

m + n = y + (e + z) + 4

m + n = -9 + (10) + 4

m + n = 5

Hope this is clear

Sudhir can you tell me how you got the bolded part?

i think the easiest way is to just solve for each necessary variable. a heavy reliance on algebra with this many variables could make the question more difficult/confusing than it ought to be.

x+4=1, so x=-3
x+e=7 : (-3)+e=7, so e=10
y+4=-5, so y=-9
y+e=n : (-9)+(10)=n, so n=1
z+e=10 : z+(10)=10, so z=0
z+4=m : (0)+4=m, so m=4

m+n=4+1=5

hope my elementary approach is helpful!