BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

a sum

Expert replies
Source: — Problem Solving |

by Mani_mba » Sun Jul 27, 2008 4:57 am
5 is my answer to ur first question.
Join the discussion

by elimenda » Sun Jul 27, 2008 5:19 am
yes it is. can you explain me how u got there?
Join the discussion

by sudhir3127 » Sun Jul 27, 2008 5:23 am
My Answer is 5.

m+ n = Z+4
n = e + y

m + n = z + 4 + e + y
4 + y = -5
y = -9

e + z = 10

m + n = y + (e + z) + 4

m + n = -9 + (10) + 4

m + n = 5

Hope this is clear
Join the discussion

by elimenda » Sun Jul 27, 2008 5:58 am
yes it is, thanks!

i didn t get the format!
Join the discussion

please explain

by ektamatta » Sun Jul 27, 2008 8:06 pm
I didn't understsnd the format either. Can anyone please explain?
Join the discussion

by gmat_oct80 » Sun Jul 27, 2008 11:39 pm
1st question: Solution is

X+ 4 = 1
So X=-3
Y+4 = -5
So y = -9,
m= z+4,
e+z = 10,
e+y = n,
x+f = 2,
So f= 5
z+f = 5
So z= 0
so m= 4,
x+e = 7,
So e = 10
M + n = z+4+e+y = 0+4+10-9 = 5



2nd question:
question is same as 1st.
Join the discussion

by evansbd » Mon Jul 28, 2008 6:13 am
sudhir3127 wrote:My Answer is 5.

m+ n = Z+4
n = e + y

m + n = z + 4 + e + y
4 + y = -5
y = -9

e + z = 10

m + n = y + (e + z) + 4

m + n = -9 + (10) + 4

m + n = 5

Hope this is clear

Sudhir can you tell me how you got the bolded part?
Join the discussion

by b.kurland » Mon Jul 28, 2008 7:08 pm
i think the easiest way is to just solve for each necessary variable. a heavy reliance on algebra with this many variables could make the question more difficult/confusing than it ought to be.

x+4=1, so x=-3
x+e=7 : (-3)+e=7, so e=10
y+4=-5, so y=-9
y+e=n : (-9)+(10)=n, so n=1
z+e=10 : z+(10)=10, so z=0
z+4=m : (0)+4=m, so m=4

m+n=4+1=5

hope my elementary approach is helpful! :wink:
Join the discussion