Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
The median of the set of values \(a, b, a+2b, a-3b, ab,\) and \(3b\) where \(a < b\) and \(b > 4,\) \(a > \dfrac{8}{3}\) is
A. \(\dfrac{(a-3b)}{2}\)
B. \(\dfrac{(a+3b)}{2}\)
C. \(\dfrac{(2a+b)}{2}\)
D. \(\dfrac{(2a-b)}{2}\)
E. \(\dfrac{(3a+b)}{2}\)
The OA is B
A. \(\dfrac{(a-3b)}{2}\)
B. \(\dfrac{(a+3b)}{2}\)
C. \(\dfrac{(2a+b)}{2}\)
D. \(\dfrac{(2a-b)}{2}\)
E. \(\dfrac{(3a+b)}{2}\)
The OA is B

















