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A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college.

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A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college.

by VJesus12 » Fri Jul 24, 2020 7:05 am

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B

C

D

E

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A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college. According to this prediction, how many students should be accepted to achieve a planned enrollment of \(x\) students?

A. \(1.05x\)
B. \(1.1x\)
C. \(1.2x\)
D. \(1.25x\)
E. \(1.8x\)

[spoiler]OA=D[/spoiler]

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Re: A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college.

by sahilaro23 » Fri Jul 24, 2020 11:29 am
suppose total students - 100
20% not attending, remaining = 80

percentage required to get total students who accept = 100/80 = 1.25x

Hence D
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Re: A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college.

by deloitte247 » Sun Jul 26, 2020 2:27 am
20% of students who are accepted will not attend college.

(100-20)% of students who are accepted will attend the college
Let y = no of students that should be accepted to achieve a planned environment of x students.

80% of y = x
$$\frac{80}{100}\cdot y=x$$
$$\frac{0.8y}{0.8}=x$$
$$y-\frac{x}{0.8}=1.25x$$
$$Answer\ is\ Option\ D$$
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