A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college.

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VJesus12: Legendary Member; Posts: 2276; Joined: Sat Oct 14, 2017 6:10 amFollowed by: 3 members

by VJesus12 » Fri Jul 24, 2020 7:05 am

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A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college. According to this prediction, how many students should be accepted to achieve a planned enrollment of $x$ students?

A. $1.05x$
B. $1.1x$
C. $1.2x$
D. $1.25x$
E. $1.8x$

[spoiler]OA=D[/spoiler]

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sahilaro23: Junior | Next Rank: 30 Posts; Posts: 17; Joined: Fri Jul 24, 2020 11:07 am; Location: INDIA

Re: A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college.

by sahilaro23 » Fri Jul 24, 2020 11:29 am

suppose total students - 100
20% not attending, remaining = 80

percentage required to get total students who accept = 100/80 = 1.25x

Hence D

deloitte247: Legendary Member; Posts: 2214; Joined: Fri Mar 02, 2018 2:22 pmFollowed by: 5 members

Re: A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college.

by deloitte247 » Sun Jul 26, 2020 2:27 am

20% of students who are accepted will not attend college.

(100-20)% of students who are accepted will attend the college
Let y = no of students that should be accepted to achieve a planned environment of x students.

80% of y = x
$$\frac{80}{100}\cdot y=x$$
$$\frac{0.8y}{0.8}=x$$
$$y-\frac{x}{0.8}=1.25x$$
$$Answer\ is\ Option\ D$$

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