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Problem Solving Help Please.

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Problem Solving Help Please.

by phoenix9801 » Wed Jun 16, 2010 3:32 am

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If you can explain step-by-step instruction I would greatly appreciate it. Be Simple...

I was able to come with 1 way to solve the problem but it toke more time for me and it does not seem efficient. So I was wondering if anyone might have easy way of solving and does not require much time.




Salesperson A's compensation for any week is $360 plus 6 percent of the portion of A's total sale above $1,000 for that week. Salesperson B's compensation for any week is 8 percent of B's total sales for that week. For what amount of total weekly sales would both salespeople earn the same compensation?
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by kvcpk » Wed Jun 16, 2010 3:40 am
comp of A = 360 + .06(sales above 1000)
comp of B = .08(Total weekly sales)

let Total weekly sales=x
b= 0.08x
a=360+0.06(x-1000)

so we neeed to find x st

0.08x=360+0.06(x-1000)
0.02x=420
x=21000

what is OA?
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by phoenix9801 » Wed Jun 16, 2010 3:54 am
kvcpk wrote:comp of A = 360 + .06(sales above 1000)
comp of B = .08(Total weekly sales)

let Total weekly sales=x
b= 0.08x
a=360+0.06(x-1000)

so we neeed to find x st

0.08x=360+0.06(x-1000)
0.02x=420
x=21000

what is OA?

Are you sure it is $21,000. I solved it in a form of Algebra. Hence I came up with x = 15,000, but I was hoping anyone might have an easer way of solving it.

360 + .06 (x - 1000) = .08

360 + .06x - 60 = .08x then solve for x
300 = .02x

15000 = x


if anyone know any easer way and simple please let me know Thanks!!!!!!!!!
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by kvcpk » Wed Jun 16, 2010 4:13 am
phoenix9801 wrote: Are you sure it is $21,000. I solved it in a form of Algebra. Hence I came up with x = 15,000, but I was hoping anyone might have an easer way of solving it.
360 + .06 (x - 1000) = .08
360 + .06x - 60 = .08x then solve for x
300 = .02x
15000 = x
if anyone know any easer way and simple please let me know Thanks!!!!!!!!!
Thanks for the correction. I messed up the subtraction again :(
0.02x = 300
x = 15000
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by selango » Wed Jun 16, 2010 4:14 am
Its 15000 only.

360+.6(x-1000)=.8x

x=15000
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by mgm » Sun Oct 24, 2010 11:35 am
I got confused because the question says A's total sale above $1000 and not the total weekly sales.
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by kapur.arnav » Sun Oct 24, 2010 11:44 am
mgm wrote:I got confused because the question says A's total sale above $1000 and not the total weekly sales.
It says total says above 1000 for THAT WEEK....
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by kapur.arnav » Sun Oct 24, 2010 11:46 am
phoenix9801 wrote:
kvcpk wrote:comp of A = 360 + .06(sales above 1000)
comp of B = .08(Total weekly sales)

let Total weekly sales=x
b= 0.08x
a=360+0.06(x-1000)

so we neeed to find x st

0.08x=360+0.06(x-1000)
0.02x=420
x=21000

what is OA?

Are you sure it is $21,000. I solved it in a form of Algebra. Hence I came up with x = 15,000, but I was hoping anyone might have an easer way of solving it.

360 + .06 (x - 1000) = .08

360 + .06x - 60 = .08x then solve for x
300 = .02x

15000 = x


if anyone know any easer way and simple please let me know Thanks!!!!!!!!!
I think this is the best way to solve this... other way could be to deal with options... but I would prefer the former... it shouldn't take more than 1 minute to solve this using the former method...
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by Scott@TargetTestPrep » Tue Dec 12, 2017 9:07 am
phoenix9801 wrote:
Salesperson A's compensation for any week is $360 plus 6 percent of the portion of A's total sale above $1,000 for that week. Salesperson B's compensation for any week is 8 percent of B's total sales for that week. For what amount of total weekly sales would both salespeople earn the same compensation?
We are given that salesperson A's compensation for any week is $360 plus 6 percent of the portion of A's total sales above $1,000 for that week.

If we let t = total sales for salesperson A, we can create the following equation:

Salesperson A's compensation = 360 + 0.06(t - 1000)

We are also given that salesperson B's compensation for any week is 8 percent of B's total sales for that week.

Since we need to determine what total sales would earn salesperson A and B the same compensation, we can also let t = the total sales for salesperson B and create the following equation:

Salesperson B's compensation = 0.08t

Let's now equate the two equations and determine t:

360 + 0.06(t - 1000) = 0.08t

360 + 0.06t - 60 = 0.08t

300 = 0.02t

30,000 = 2t

15,000 = t

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by Shitandi » Sun Apr 15, 2018 11:46 pm
Scott@TargetTestPrep wrote:
phoenix9801 wrote:
Salesperson A's compensation for any week is $360 plus 6 percent of the portion of A's total sale above $1,000 for that week. Salesperson B's compensation for any week is 8 percent of B's total sales for that week. For what amount of total weekly sales would both salespeople earn the same compensation?
We are given that salesperson A's compensation for any week is $360 plus 6 percent of the portion of A's total sales above $1,000 for that week.

If we let t = total sales for salesperson A, we can create the following equation:

Salesperson A's compensation = 360 + 0.06(t - 1000)

We are also given that salesperson B's compensation for any week is 8 percent of B's total sales for that week.

Since we need to determine what total sales would earn salesperson A and B the same compensation, we can also let t = the total sales for salesperson B and create the following equation:

Salesperson B's compensation = 0.08t

Let's now equate the two equations and determine t:

360 + 0.06(t - 1000) = 0.08t

360 + 0.06t - 60 = 0.08t

300 = 0.02t

30,000 = 2t

15,000 = t
Why use 't' for both and assume that A's total sales for the week are the same as B's sales for the week?
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