A rectangular box is 12 inches wide, 16 inches long, and 20 inches high. Which of the following is closest to the longest straight-line distance between any two corners of the box?
A. 22 inches
B. 25 inches
C. 28 inches
D. 30 inches
E. 34 inches
The OA is C.
Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.
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A rectangular box is 12 inches wide, 16 inches long...
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GMATWisdom
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Longest distance is the biggest diagonal=√(L^2+B^2+H^2) = √(〖〖12〗^2++〖16〗^2+20〗^(2 ) )AAPL wrote:A rectangular box is 12 inches wide, 16 inches long, and 20 inches high. Which of the following is closest to the longest straight-line distance between any two corners of the box?
A. 22 inches
B. 25 inches
C. 28 inches
D. 30 inches
E. 34 inches
The OA is C.
Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.
+√(144+256+400)
=√800 =twenty eight point something because 〖28〗^2=784
Hence C is the right option
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Scott@TargetTestPrep
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We can use the following formula to calculate the diagonal (or d):AAPL wrote:A rectangular box is 12 inches wide, 16 inches long, and 20 inches high. Which of the following is closest to the longest straight-line distance between any two corners of the box?
A. 22 inches
B. 25 inches
C. 28 inches
D. 30 inches
E. 34 inches
The OA is C.
Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.
d^2 = 12^2 + 20^2 + 16^2
d^2 = 144 + 400 + 256
d^2 = 800
d = √800 = 20√2, so d is about 20 * 1.4 = 28.
Answer: C
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