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A rectangular box is 12 inches wide, 16 inches long...

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by AAPL » Tue Dec 19, 2017 3:13 pm
A rectangular box is 12 inches wide, 16 inches long, and 20 inches high. Which of the following is closest to the longest straight-line distance between any two corners of the box?

A. 22 inches
B. 25 inches
C. 28 inches
D. 30 inches
E. 34 inches

The OA is C.

Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.
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by GMATWisdom » Wed Dec 20, 2017 6:28 am
AAPL wrote:A rectangular box is 12 inches wide, 16 inches long, and 20 inches high. Which of the following is closest to the longest straight-line distance between any two corners of the box?

A. 22 inches
B. 25 inches
C. 28 inches
D. 30 inches
E. 34 inches

The OA is C.

Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.
Longest distance is the biggest diagonal=√(L^2+B^2+H^2) = √(〖〖12〗^2++〖16〗^2+20〗^(2 ) )
+√(144+256+400)
=√800 =twenty eight point something because 〖28〗^2=784
Hence C is the right option
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by Scott@TargetTestPrep » Thu Sep 12, 2019 6:21 pm
AAPL wrote:A rectangular box is 12 inches wide, 16 inches long, and 20 inches high. Which of the following is closest to the longest straight-line distance between any two corners of the box?

A. 22 inches
B. 25 inches
C. 28 inches
D. 30 inches
E. 34 inches

The OA is C.

Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.
We can use the following formula to calculate the diagonal (or d):

d^2 = 12^2 + 20^2 + 16^2

d^2 = 144 + 400 + 256

d^2 = 800

d = √800 = 20√2, so d is about 20 * 1.4 = 28.

Answer: C

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