diebeatsthegmat wrote:15 lts are taken of from a container full of liquid A and replaced with Liquid B. Again 15 more lts of the mixture is taken and replaced with liquid B. After this process, if the container contains Liquid A and B in the ratio 9:16,What is the capacity of the container?
A:45
B:25
C:37.5
D:36
E:42
We could also use the formula for REPEATED FRACTIONAL CHANGE.
If amount
x DECREASES by fraction
a/b exactly
n times:
Final amount = x * (1 - a/b)^n.
In the problem at hand (as noted in my post above):
The original amount of A = x.
The final amount = (9/25)x.
The fractional decrease = 15/x.
Since the volume decreases TWICE, n = 2.
Plugging these values into the formula, we get:
(9/25)x = x * (1 - 15/x)²
9/25 = (1 - 15/x)²
3/5 = 1 - 15/x
15/x = 2/5
2x = 75
x = 37.5.
Note that if amount
x INCREASES by fraction
a/b exactly
n times, the formula is as follows:
Final amount = x * (1 + a/b)^n.
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