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Source: — Data Sufficiency |
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by liferocks » Wed May 05, 2010 7:26 am
from 1
x+y=3xy
or 1/x+1/y=3...dividing both sides by xy
or 2/x+2/y=6...sufficient

from 2

no information on the value of x or y hence not sufficient
Ans option A
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by kstv » Wed May 05, 2010 7:32 am
(1) x+y=3xy multiply both sides by 2/xy
2x/xy + 2y/xy = 3xy*2/xy
2/y+2/x = 6
Suff
(2) x = y
x & y can be any value
so not necessarily 4/x = 6
Insuff
IMO A
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by ssuarezo » Wed May 05, 2010 7:38 am
Hi Liferocks:

Actually the question is: 2/x + 2/y = 6, but if you simplify this stm, you'll get x + y = 3xy, so stm1 is the same as the question, so it s not suficient. Am I wrong?

Stm2:

Staritng from x + y = 3xy (simplified from question stem), if x = y, then for x=-2, y=2, the stm is false, if they were fractions, for example 1/2 , stm is false also. So, IMHO, it s B.

Did I miss something?

Thanks
Silvia
liferocks wrote:from 1
x+y=3xy
or 1/x+1/y=3...dividing both sides by xy
or 2/x+2/y=6...sufficient
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by mchaubey » Wed May 05, 2010 8:46 am
ssuarezo wrote:Hi Liferocks:

Actually the question is: 2/x + 2/y = 6, but if you simplify this stm, you'll get x + y = 3xy, so stm1 is the same as the question, so it s not suficient. Am I wrong?

Stm2:

Staritng from x + y = 3xy (simplified from question stem), if x = y, then for x=-2, y=2, the stm is false, if they were fractions, for example 1/2 , stm is false also. So, IMHO, it s B.

Did I miss something?

Thanks
Silvia
liferocks wrote:from 1
x+y=3xy
or 1/x+1/y=3...dividing both sides by xy
or 2/x+2/y=6...sufficient
By simplifying the given equation we get statement 1
Thus statement 1 is sufficient if its true
while in case of statement 2 we have more than one value of x and y for it to be suff.

Thus Ans is A
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by akhpad » Wed May 05, 2010 9:01 am
Yup; A
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