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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## A men's basketball league assigns every player ##### This topic has 2 expert replies and 0 member replies ### Top Member ## A men's basketball league assigns every player A men's basketball league assigns every player a two-digit number for the back of his jersey. If the league uses only the digits 1-5, what is the maximum number of players that can join the league such that no player has a number with a repeated digit (e.g. 22), and no two players have the same number? A. 20 B. 21 C. 22 D. 24 E. 25 Can some experts show me the best solution in this? OA A ### GMAT/MBA Expert Legendary Member Joined 14 Jan 2015 Posted: 2667 messages Followed by: 122 members Upvotes: 1153 GMAT Score: 770 Top Reply lheiannie07 wrote: A men's basketball league assigns every player a two-digit number for the back of his jersey. If the league uses only the digits 1-5, what is the maximum number of players that can join the league such that no player has a number with a repeated digit (e.g. 22), and no two players have the same number? A. 20 B. 21 C. 22 D. 24 E. 25 Can some experts show me the best solution in this? OA A If there were no restrictions, and you had 5 options for the first digit and 5 options for the second digit, there'd have been 5*5 = 25 unique numbers. But we know we can't have repeated numbers, so now we have to eliminate 11, 22, 33, 44, 55 --> 5 numbers we have to eliminate. 25 - 5 = 20. The answer is A _________________ Veritas Prep | GMAT Instructor Veritas Prep Reviews Save$100 off any live Veritas Prep GMAT Course

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BTGmoderatorDC wrote:
A men's basketball league assigns every player a two-digit number for the back of his jersey. If the league uses only the digits 1-5, what is the maximum number of players that can join the league such that no player has a number with a repeated digit (e.g. 22), and no two players have the same number?

A. 20
B. 21
C. 22
D. 24
E. 25

Can some experts show me the best solution in this?

OA A
We need to determine how many two-digit numbers can be created from 5 digits (1 to 5, inclusive), and no digits can be repeated. Since order matters, we have a permutation. Thus, the number of ways to create two-digit numbers is 5P2 = 5!/(5 - 2)! = 5 x 4 = 20.

Alternate Solution:

If repeated digits were allowed, there would be 25 possibilities since for each digit we would have 5 choices. Among these 25 possibilities, 5 of them are repeated digit numbers (which are 11, 22, 33, 44, and 55). Thus, without the repeated digits, there are 25 - 5 = 20 numbers possible.

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