rtaha2412 wrote:The probability that a visitor at the mall buys a pack of candy is 30%. If three visitors come to the mall today, what is the probability that exactly two visitors will buy a pack of candy?
a 0.343
b 0.147
c 0.189
d 0.063
e 0.027
P(1st visitor buys candy) = 3/10
P(2nd visitor buys candy) = 3/10
P(3rd visitor doesn't buy candy) = 7/10
Since we need all of the events above to happen together, we multiply the fractions: 3/10 * 3/10 * 7/10 = 63/1000.
Since the visitor who doesn't buy candy could be 1st, 2nd, or 3rd, we multiply the result above by 3:
3 * 63/1000 = 189/1000.
The correct answer is
C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3