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A manager must select 2 people from a

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A manager must select 2 people from a

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A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16

The OA is D.

What is the best way to solve this PS question? Should I use combinatorial theory?

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Hello Vincen.

Let's take a look at your question.

We have to pick 2 people from a 4 people group. And the order matter. We have 2 places: _____ _____.

For the first place we have 4 options and for the second place, we have 3 options.

So, there are 4*3=12 different ways to pick the 2 people.

So, the correct answer is D.

I hope this can help you.

Feel free to ask me again if you have a doubt.

Regards.

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Vincen wrote:
A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16
Since we have specific positions in the group, order matters, and so we have a permutation. Thus, the number of ways to select a steward and a treasurer from 4 employees is 4P2 = 4!/2! = 4 x 3 = 12 ways.

Answer: D

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jeff@targettestprep.com



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Hi Vincen,

We're told that a manager must select 2 people from a group of 4 employees; one person will be the shop steward and the other person will be the treasurer. We're asked for the number of different ways that this can be accomplished.

Starting with the shop steward, there are 4 options. Once once of those people is chosen...
We then choose for the treasurer, so there will be 3 options.

Total ways = (4)(3) = 12

Final Answer: D

GMAT assassins aren't born, they're made,
Rich

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Contact Rich at Rich.C@empowergmat.com

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