BTGmoderatorDC wrote: ↑

Sun Apr 26, 2020 6:05 pm

A man walking at a constant rate of 4 miles per hour is passed by a woman traveling in the same direction along the same path at a constant rate of 20 miles per hour. The woman stops to wait for the man 5 minutes after passing him, while the man continues to walk at his constant rate. How many minutes must the woman wait until the man catches up?

(A) 16 mins
(B) 20 mins
(C) 24 mins
(D) 25 mins
(E) 28 mins

OA B

Source: Veritas Prep

Once the woman passes the man, the relative speed of the woman is 20 – 4 = 16 mph

Distance recovered by the woman in 5 minutes = 16*(5/60) = 4/3 miles

Since the woman has stopped now, for the man to catch her, he has to travel 4/3 miles @ 4mph

Thus, time taken by the man = (4/3)/4 =1/3 hours = 60/3 = 20 minues.

The correct answer: B

Hope this helps!

-Jay
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BTGmoderatorDC wrote: ↑

Sun Apr 26, 2020 6:05 pm

A man walking at a constant rate of 4 miles per hour is passed by a woman traveling in the same direction along the same path at a constant rate of 20 miles per hour. The woman stops to wait for the man 5 minutes after passing him, while the man continues to walk at his constant rate. How many minutes must the woman wait until the man catches up?

(A) 16 mins
(B) 20 mins
(C) 24 mins
(D) 25 mins
(E) 28 mins

After 5 minutes the distance between the man and woman is:

20(1/12) - 4(1/12) = 20/12 - 4/12 = 16/12 = 4/3 miles

Thus, it takes the man (4/3)/4 = 4/12 = 1/3 hour, or 20 minutes, to catch up with the woman.

Answer: B