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A man travels from one city to another city that is 'd' mile

Expert replies
by vinni.k » Thu Jan 24, 2013 9:17 pm
A man travels from one city to another city that is 'd' miles apart, in time 't' hours and reaches 3 hours late. At what speed should he travel in order to reach an hour early ?

(A) d/(t-4) miles/hour
(B) d/(t-3) miles/hour
(C) d/(t-1) miles/hour
(D) d/(t-3/2) miles/hour
(E) cannot be determined

Answer is A

Thanks & Regards
Vinni
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Source: — Problem Solving |

by hemant_rajput » Thu Jan 24, 2013 11:08 pm
A man traveling at x speed will reach 3 hours late. so if he want to reach at normal time he should travel at speed d/(t-3). Now if he want to reach 1 hour early to his usual time he has to travel d/(t-4), which is option a.

if you are still confused take some value for d and t; say d =100 and t =10.
so his current speed is 100/10 = 10 miles/hour. His usual speed will allow him to reach 3 hour early 100/7 = 14.2857 miles/hour.Now he want to reach 1hour early to his usual time his speed will 100/6 = 16.67 miles/hour.
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by lunarpower » Sat Jan 26, 2013 12:23 am
this problem can provide some valuable practice -- especially in using the number-picking method described by the poster above -- but it's not well written (and definitely not written as conscientiously as the official problems are).

given the wording of this problem, the man could just as well reach his destination an hour early by, say, traveling at exactly the same speed but leaving four hours earlier, or by starting from a point that's closer to the destination. (as transcribed, the problem says nothing about the time or point of departure, so there's no good reason to assume that either is the same as in the original situation.)

this may seem like nitpicking, but it's not -- a MAJOR part of success in gmat math, especially in data sufficiency, comes from establishing exactly which qualities are specified and which quantities aren't.
practicing with sloppily written questions (like this one) can actually undermine the sort of attentive reading that's necessary on the exam.
Ron has been teaching various standardized tests for 20 years.

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by vinni.k » Sat Feb 02, 2013 12:14 pm
Thanks Ron. Even i was finding hard to understand the wording. The question says "reaches 3 hours late." I am still confused why are we taking (t-3) when in fact the man was late by 3 hrs i.e t + 3

His usual time, suppose, is 10 hrs, but the guy reaches after 13 hrs. He needs to reach an hour earlier i.e 12 hrs. So, t + 3 - 1 = t + 2.

A bit confusing or i am missing something.

Regards
Vinni
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by Tommy Wallach » Sat Feb 02, 2013 1:41 pm
Hey Vinni,

You're right that he gets there three hours late. However, the method described by Hemant is setting that "three hours later" as right on time. Then, he is calculating what the time would be for "four hours early" from that new benchmark.

If you really wanted to, you could set the original time as t+3 (three hours late), then solve back to t-1 (four hours earlier). It won't actually make any difference, because the four hour difference is the same whether it's t and t+4 or t-1 and t+3.

Does that make more sense?

-t

P.S. I want to second Ron's annoyance with the wording of the question. People post a TON of questions on here that do not simulate the real test. If you ever read a single grammatical error in a question, odds are good it comes from a dangerous source. For example, in this case it says "A man traveling at x speed will reach 3 hours late." A grammatically correct sentence would say "A man traveling at x miles per hour will reach his destination three hours late." A grammatically correct version of the whole question might say:

A man travels from City X to City Y, which is d miles away from City X. He travels in a straight line, and arrives in City Y three hours later than he intended. If the trip took t hours, at what speed should he have travelled if he'd wanted to leave at the same time but arrive an hour earlier than he intended?
Tommy Wallach, Company Expert
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