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A little help please

Expert replies
Source: — Problem Solving |

by Brent@GMATPrepNow » Fri Oct 21, 2016 4:48 pm
fambrini wrote:If k ≠ 0, 1 or -1, is 1 / k > 0?

1) 1 / k - 1 > 0

2) 1 / k + 1 > 0

OA: A
This question would benefit from some parentheses.
Does 1 / k - 1 mean 1/(k-1) or (1/k) - 1?
Brent Hanneson - Creator of GMATPrepNow.com
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by fambrini » Fri Oct 21, 2016 4:53 pm
Well, sorry about this. In my original prompt it looks just like this.

However, I would interpret this as 1 / (k - 1).

Thanks!
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by GMATGuruNY » Sat Oct 22, 2016 3:01 am
fambrini wrote:If k ≠ 0, 1 or -1, is 1 / k > 0?

1) 1/(k-1) > 0

2) 1/(k+1) > 0
In order for 1/k to be positive, k must be positive.
Question stem, rephrased:
Is k>0?

Statement 1:
In order for 1/(k-1) to be positive, k-1 must be positive:
k-1>0
k>1.
Thus, k>0.
SUFFICIENT.

Statement 2:
In order for 1/(k+1) to be positive, k+1 must be positive:
k+1>0
k>-1
If k=2, the answer to the question stem is YES.
If k=-1/2, the answer to the question stem is NO.
INSUFFICIENT.

The correct answer is A.
Last edited by GMATGuruNY on Sat Oct 22, 2016 7:56 am, edited 1 time in total.
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by fambrini » Sat Oct 22, 2016 7:09 am
I thought about this solution. However, the statement confused me with the 1 / k - 1 fraction. Thanks a lot!
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by Mo2men » Sat Oct 22, 2016 7:44 am
GMATGuruNY wrote:
fambrini wrote:If k ≠ 0, 1 or -1, is 1 / k > 0?

1) 1/(k-1) > 0

2) 1/(k+1) > 0
In order for 1/k to be positive, k must be positive.
Question stem, rephrased:
Is k>0?

Statement 1:
In order for 1/(k-1) to be positive, k-1 must be positive:
k-1>0
k>1.
Thus, k>0.
SUFFICIENT.

Statement 2:
In order for 1/(k+1) to be positive, k+1 must be positive:
k+1>0
k>-1
If k=1, the answer to the question stem is YES.
If k=-1/2, the answer to the question stem is NO.
INSUFFICIENT.

The correct answer is A.
HI Mitch,

As per the question stem, K CAN'T be 1.
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by GMATGuruNY » Sat Oct 22, 2016 7:57 am
Mo2men wrote:HI Mitch,

As per the question stem, K CAN'T be 1.
Good catch.
I've amended my post accordingly.
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My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

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by Matt@VeritasPrep » Fri Oct 28, 2016 12:11 am
We might also want to reroute this post to the DS forum.
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by Mo2men » Fri Oct 28, 2016 12:32 am
GMATGuruNY wrote:
fambrini wrote:If k ≠ 0, 1 or -1, is 1 / k > 0?

1) 1/(k-1) > 0

2) 1/(k+1) > 0
In order for 1/k to be positive, k must be positive.
Question stem, rephrased:
Is k>0?

Statement 1:
In order for 1/(k-1) to be positive, k-1 must be positive:
k-1>0
k>1.
Thus, k>0.
SUFFICIENT.

Statement 2:
In order for 1/(k+1) to be positive, k+1 must be positive:
k+1>0
k>-1
If k=2, the answer to the question stem is YES.
If k=-1/2, the answer to the question stem is NO.
INSUFFICIENT.

The correct answer is A.
Hi Mitch,

what would be the critical points in this problem?

In statement 1, I assume they are 0 & 1

In statement 2, they are -1 & 0

Do I miss anything?
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by Matt@VeritasPrep » Fri Oct 28, 2016 1:01 am
Mo2men wrote: In statement 1, I assume they are 0 & 1

In statement 2, they are -1 & 0
You're probably fine just thinking of 1 in S1 and -1 in S2. (0 isn't as critical, since all that really matters is whether your denominator is + or -.)
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by Mo2men » Fri Oct 28, 2016 1:23 am
Matt@VeritasPrep wrote:
Mo2men wrote: In statement 1, I assume they are 0 & 1

In statement 2, they are -1 & 0
You're probably fine just thinking of 1 in S1 and -1 in S2. (0 isn't as critical, since all that really matters is whether your denominator is + or -.)
i agree with you but I though in 0 as stem ask for 1/k so 0 would be critical point. Also, it would help me in statement 2 to check points (such as -1/2) between -1 & 0. otherwise, I would check point such 2 as it is greater than -1.

You may argue that I need to check negative fractions to ensure the validity of the statement. However, I find it easy to draw critical points on number line with those points and determine range.
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