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A lawn care company has five employees, and there are ten

Expert replies
by Gmat_mission » Mon Jun 11, 2018 2:00 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

A lawn care company has five employees, and there are ten houses that need care on a given day. How many different ways can the company assign the five employees to work at the different houses on that day if each employee works at two houses?

(A) 50
(B) 2!/1!
(C) 120
(D) 10!/5!
(E) 10!

[spoiler]OA=D[/spoiler]

I am confused. Could anyone give me a detailed explanation here? Please. I'd be thankful.
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Source: — Problem Solving |

by GMATGuruNY » Mon Jun 11, 2018 3:12 am
The posted problem has been transcribed from the original source -- the book GMAT for Dummies -- incorrectly.
In the book, the prompt reads as follows:
Gmat_mission wrote:A lawn care company has five employees, and there are ten houses that need care on a given day. How many different ways can the company assign the five employees to work at the different houses on that day if each employee provides service for just one home?

(A) 50
(B) 2!/1!
(C) 120
(D) 10!/5!
(E) 10!
Number of houses that could be assigned to the first employee = 10. (Any of the 10 houses.)
Number of houses that could be assigned to the second employee = 9. (Any of the 9 remaining houses.)
Number of houses that could be assigned to the third employee = 8. (Any of the 8 remaining houses.)
Number of houses that could be assigned to the fourth employee = 7. (Any of the 7 remaining houses.)
Number of houses that could be assigned to the fifth employee = 6. (Any of the 6 remaining houses.)
To combine these options, we multiply:
10*9*8*7*6.

The product above is equivalent to D:
10!/5! = 10*9*8*7*6.

The correct answer is D.
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Gmat_mission wrote:A lawn care company has five employees, and there are ten houses that need care on a given day. How many different ways can the company assign the five employees to work at the different houses on that day if each employee works at two houses?

(A) 50
(B) 2!/1!
(C) 120
(D) 10!/5!
(E) 10!

[spoiler]OA=D[/spoiler]

I am confused. Could anyone give me a detailed explanation here? Please. I'd be thankful.
Number of ways to select 5 houses from 10: 10!/5!*5!

Number of ways a group of 5 houses can be distributed among 5 employees: 5!

Total number of ways: (10!/5!*5!)*5! = [spoiler]10!/5!, D[/spoiler]
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hi

by Jeff@TargetTestPrep » Wed Jun 13, 2018 3:40 pm
Gmat_mission wrote:A lawn care company has five employees, and there are ten houses that need care on a given day. How many different ways can the company assign the five employees to work at the different houses on that day if each employee provides service for just one home?

(A) 50
(B) 2!/1!
(C) 120
(D) 10!/5!
(E) 10!
Number of ways the houses could be assigned to the first employee = 10

Number of ways the houses could be assigned to the second employee = 9

Number of ways the houses could be assigned to the third employee =8

Number of ways the houses could be assigned to the fourth employee = 7

Number of ways the houses that could be assigned to the fifth employee = 6

So the total number of ways is

10 x 9 x 8 x 7 x 6 = 10!/5!

Answer: D

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