A hiker walked for two days. On the second day the hiker walked 2 hours longer and at an average speed...

Question

Source: GMAT Paper Tests A hiker walked for two days. On the second day, the hiker walked 2 hours longer and at an average speed of 1 mile per hour faster than he walked on the first day. If during the two days he walked a total of 64 miles and spent a total of 18 hours walking, what was his average speed on the first day? A. 2 mph B. 3 mph C. 4 mph D. 5 mph E. 6 mph The OA is B

Brent@GMATPrepNow · Answer

BTGmoderatorLU wrote: ↑Wed Apr 15, 2020 4:58 am Source: GMAT Paper Tests A hiker walked for two days. On the second day, the hiker walked 2 hours longer and at an average speed of 1 mile per hour faster than he walked on the first day. If during the two days he walked a total of 64 miles and spent a total of 18 hours walking, what was his average speed on the first day? A. 2 mph B. 3 mph C. 4 mph D. 5 mph E. 6 mph The OA is B If we let x = the hiker's walking speed on day 1, then x+1 = the hiker's walking speed on day 2 (since the hiker walked 1 mph faster on the second day) So, the hiker's AVERAGE speed will be BETWEEN x and x+1 mph The hiker walked 64 miles and 18 hours. Average speed = distance/time = 64/18 ≈ 3.5 mph So, according to the above property, it must be the case that x = 3 mph, and x+1 = 4 mph Answer: B Cheers, Brent

swerve · Answer

BTGmoderatorLU wrote: ↑Wed Apr 15, 2020 4:58 am Source: GMAT Paper Tests A hiker walked for two days. On the second day, the hiker walked 2 hours longer and at an average speed of 1 mile per hour faster than he walked on the first day. If during the two days he walked a total of 64 miles and spent a total of 18 hours walking, what was his average speed on the first day? A. 2 mph B. 3 mph C. 4 mph D. 5 mph E. 6 mph The OA is B Let $x$ be the number of miles in first day; $64-x =$ number of miles in second day given, $t+ t+2 =18 \Rightarrow t=10$ Speed in the first day $=$ speed in the second day $- 1$ Therefore, $\dfrac{64−x}{10} -\dfrac{x}{8} = 1$ $x = 24$ Therefore, speed $= \dfrac{d}{t} = \dfrac{24}{8} = 3$

Scott@TargetTestPrep · Answer

BTGmoderatorLU wrote: ↑Wed Apr 15, 2020 4:58 am Source: GMAT Paper Tests A hiker walked for two days. On the second day, the hiker walked 2 hours longer and at an average speed of 1 mile per hour faster than he walked on the first day. If during the two days he walked a total of 64 miles and spent a total of 18 hours walking, what was his average speed on the first day? A. 2 mph B. 3 mph C. 4 mph D. 5 mph E. 6 mph The OA is B We can let t = the number of hours and r = the speed he walked on the first day. We can create the equations: t + t + 2 = 18 and tr + (t +2)(r + 1) = 64 Solving the first equation, we have: 2t = 16 t = 8 Now, substituting t = 8 into the second equation, we have: 8r + 10(r + 1) = 64 8r + 10r + 10 = 64 18r = 54 r = 3 Answer: B

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A hiker walked for two days. On the second day the hiker walked 2 hours longer and at an average speed...

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Re: A hiker walked for two days. On the second day the hiker walked 2 hours longer and at an average speed...

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