BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

a fish colony

Expert replies
by rahul.s » Tue Feb 23, 2010 2:49 am
A fish colony is called "unstable" if, at the end of the year, the total increase in the sum of the lengths of the fish in the colony is more than 15% greater than the sum of the lengths of the fish at the beginning of the year. In a colony of three fish, the length of the longest fish increased by 20% by the end of the year, and the length of the other two fish increased by 10% by the end of the year. Is this fish colony unstable?

(1) The original length of the longest fish was 10 inches, and the original length of the second-longest fish was 7 inches.
(2) The original length of the shortest fish was 5 inches

OA: C
Source: Knewton
Join the discussion
Source: — Data Sufficiency |

by harsh.champ » Tue Feb 23, 2010 2:56 am
rahul.s wrote:A fish colony is called "unstable" if, at the end of the year, the total increase in the sum of the lengths of the fish in the colony is more than 15% greater than the sum of the lengths of the fish at the beginning of the year. In a colony of three fish, the length of the longest fish increased by 20% by the end of the year, and the length of the other two fish increased by 10% by the end of the year. Is this fish colony unstable?

(1) The original length of the longest fish was 10 inches, and the original length of the second-longest fish was 7 inches.
(2) The original length of the shortest fish was 5 inches

OA: C
Source: Knewton
I cant understand the bold-faced part.
Is the question correctly typed??
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.

"Keep Walking" - Johnny Walker :P
Join the discussion

by rahul.s » Tue Feb 23, 2010 3:05 am
harsh.champ wrote:
rahul.s wrote:A fish colony is called "unstable" if, at the end of the year, the total increase in the sum of the lengths of the fish in the colony is more than 15% greater than the sum of the lengths of the fish at the beginning of the year. In a colony of three fish, the length of the longest fish increased by 20% by the end of the year, and the length of the other two fish increased by 10% by the end of the year. Is this fish colony unstable?

(1) The original length of the longest fish was 10 inches, and the original length of the second-longest fish was 7 inches.
(2) The original length of the shortest fish was 5 inches

OA: C
Source: Knewton
I cant understand the bold-faced part.
Is the question correctly typed??
yeah, it's correct.
Join the discussion

by rahul.s » Tue Feb 23, 2010 3:07 am
at the end of a year, the sum of their lengths shouldn't be greater than 15% of what it was at the start of the year. if it is greater than 15%, then they're unstable.
Join the discussion

by kstv » Tue Feb 23, 2010 3:24 am
To find the % growth, we need the sums of their measurement at the beginning. Percentage growth individually is given.
(1) Insuff we still need the length of the shortest.
(2) Suff.

No need to calculate, but the answer will either be negative or affirmative. So C.
Join the discussion

by ajith » Tue Feb 23, 2010 3:33 am
rahul.s wrote:A fish colony is called "unstable" if, at the end of the year, the total increase in the sum of the lengths of the fish in the colony is more than 15% greater than the sum of the lengths of the fish at the beginning of the year. In a colony of three fish, the length of the longest fish increased by 20% by the end of the year, and the length of the other two fish increased by 10% by the end of the year. Is this fish colony unstable?

(1) The original length of the longest fish was 10 inches, and the original length of the second-longest fish was 7 inches.
(2) The original length of the shortest fish was 5 inches

OA: C
Source: Knewton
Let x , y , z be the lengths of longest, second longest and shortest fishes respectively at the start of the year.

1. x = 10, y =7; x' = 12 , y' = 7.7 and z' = 1.1 z

The new average = (19.7+1.1z)/3
The old average = (17+z)/3

Let us take 2 cases z=7 and z=1

if z=10 ; The ratio of new and old average= (19.7+7.7)/(17+7) = 1.14
14% increase
if z= 1 ; the ratio is = (19.7+1.1)/(17+1) =1.155
15.5% increase

Not sufficient

2) Not Sufficient since it doesnt tell anything about the other two fish's ; lengths

Combining

New average = (12+7.7+5.5) /3= 25.2/3 = 8.4
Old average = (10+7+5)/3 =22/3

ratio = 25.2/22 =1.145

Less than 15% , sufficient to decide whether the colony is unstable
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion