BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

A cow is tethered to the corner of a rectangular shed.

Expert replies
by BTGmoderatorLU » Sat Dec 08, 2018 4:58 am

Timer

00:00

Answers

A

0%

B

0%

C

0%

D

0%

E

0%

Stats

Difficulty

0% CorrectAvg —

0% IncorrectAvg —

Source: Magoosh

Image

A cow is tethered to the corner of a rectangular shed. If the length of the rope is 5, and the shed has length 4 and width 3, what is the maximum area that is accessible to the cow? (The cow cannot enter the shed).

$$A.\ 12\pi$$
$$B.\ 15\pi$$
$$C.\ 16\pi$$
$$D.\ 18\pi$$
$$E.\ 20\pi$$

The AO is E
Join the discussion
Source: — Problem Solving |

BTGmoderatorLU wrote:Source: Magoosh

Image

A cow is tethered to the corner of a rectangular shed. If the length of the rope is 5, and the shed has length 4 and width 3, what is the maximum area that is accessible to the cow? (The cow cannot enter the shed).

$$A.\ 12\pi$$
$$B.\ 15\pi$$
$$C.\ 16\pi$$
$$D.\ 18\pi$$
$$E.\ 20\pi$$
Very nice problem! Be sure you understand the figure below:

Image

$$? = {3 \over 4}\pi \cdot {5^2} + {1 \over 4}\pi \cdot {1^2} + {1 \over 4}\pi \cdot {2^2} = {\pi \over 4}\left( {80} \right) = 20\pi $$

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
Join the discussion