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A contractor

Expert replies
by Xbond » Fri Aug 14, 2009 12:21 am
Hi there,

I would like to know the simplest process to resolve this DS. Explanation is requested.

A contractor combined x tons of a gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that contained 2 percent gravel G, by weight, to produce z tons of a mixture that was 5 percent gravel G by weight. What is the value of x ?

(1) y = 10
(2) z = 16
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Source: — Data Sufficiency |

by pavell » Fri Aug 14, 2009 12:33 am
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by tohellandback » Fri Aug 14, 2009 12:55 am
IMO C
the equation you get is

.1X+.02Y=.05Z
we need both Y and Z to get X

hence C
The powers of two are bloody impolite!!
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by ankit1383 » Fri Aug 14, 2009 2:16 am
tohellandback wrote:IMO C
the equation you get is

.1X+.02Y=.05Z
we need both Y and Z to get X

hence C
.1X + .02Y=.05(X+Y)

since Z is made up of both X and Y
or this thing we cnt assume????

If we follow the above equation the answer is D
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by tohellandback » Fri Aug 14, 2009 2:19 am
ankit1383 wrote:
tohellandback wrote:IMO C
the equation you get is

.1X+.02Y=.05Z
we need both Y and Z to get X

hence C
.1X + .02Y=.05(X+Y)

since Z is made up of both X and Y
or this thing we cnt assume????

If we follow the above equation the answer is D
thanks. you are right. I missed that.
answer must be D
The powers of two are bloody impolite!!
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by Xbond » Fri Aug 14, 2009 12:02 pm
how do you find the value of x with statement 2 in order to say D is right answer :

.1X + .02Y=.05(X+Y)
.1X + .02Y=.05(Z)
.1X + .02Y=.05(16)
.1X + .02Y=8

at the end you have 2 differents variables except whether you assume X+Y =8+8, no ?
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by Xbond » Fri Aug 14, 2009 12:04 pm
how do you find the value of x with statement 2 in order to say D is right answer :

.1X + .02Y=.05(X+Y)
.1X + .02Y=.05(Z)
.1X + .02Y=.05(16)
.1X + .02Y=8

at the end you have 2 differents variables except whether you assume X+Y =8+8, no ?
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by niraj_a » Fri Aug 14, 2009 1:59 pm
Xbond,

can't Y be equal to 1-X?
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by anand0408 » Sat Aug 15, 2009 2:46 am
Y is Z-X

So you have 2 eqns and 2 variables
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by Xbond » Mon Aug 17, 2009 5:15 am
many thks guys

OA is D
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by jjk » Mon Aug 17, 2009 3:48 pm
Yes, Y is simply Z - X.

If we replace Y with Z - X in the equation, we get:

.10X + .02(16 - X) = .8

X = 6
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