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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## A certain team has 12 members, including Joey. A three..... tagged by: VJesus12 ##### This topic has 2 expert replies and 0 member replies ## A certain team has 12 members, including Joey. A three..... A certain team has 12 members, including Joey. A three-member relay team will be selected as follows: one of the 12 members is to be chosen at random to run first, one of the remaining 11 members is to be chosen at random to run second, and one of the remaining 10 members is to be chosen at random to run third. What is the probability that Joey will be chosen to run second or third? A. 1/1,320 B. 1/132 C. 1/110 D. 1/12 E. 1/6 The OA is the option E. Experts, how can I solve this PS question? The first time, the probability that Joey wouldn't be chosen is 11/12? Or how should I start the solution? ### GMAT/MBA Expert GMAT Instructor Joined 25 Apr 2015 Posted: 1776 messages Followed by: 14 members Upvotes: 43 Top Reply VJesus12 wrote: A certain team has 12 members, including Joey. A three-member relay team will be selected as follows: one of the 12 members is to be chosen at random to run first, one of the remaining 11 members is to be chosen at random to run second, and one of the remaining 10 members is to be chosen at random to run third. What is the probability that Joey will be chosen to run second or third? A. 1/1,320 B. 1/132 C. 1/110 D. 1/12 E. 1/6 The probability Joey will be chosen to run second is: 11/12 x 1/11 x 10/10 = 1/12 The probability Joey will be chosen to run third is: 11/12 x 10/11 x 1/10 = 1/12 Thus the probability that he will chosen to run second or third is: 1/12 + 1/12 = 2/12 = 1/6 Answer: E _________________ Scott Woodbury-Stewart Founder and CEO ### GMAT/MBA Expert Elite Legendary Member Joined 23 Jun 2013 Posted: 9942 messages Followed by: 492 members Upvotes: 2867 GMAT Score: 800 Hi VJesus12, We're told that a certain team has 12 members, including Joey. A three-member relay team will be selected as follows: one of the 12 members is to be chosen at random to run first, one of the remaining 11 members is to be chosen at random to run second, and one of the remaining 10 members is to be chosen at random to run third. We're asked for the probability that Joey will be chosen to run second or third. There are a couple of different ways to do this type of math; here's how you can break the calculation down into two 'pieces': The probability that Joey is chosen to run second is: (Not Joey 1st)(Joey 2nd)(Not Joey 3rd) = (11/12)(1/11)(10/10) = 1/12 The probability that Joey is chosen to run third is: (Not Joey 1st)(Not Joey 2nd)(Joey 3rd) = (11/12)(10/11)(1/10) = 1/12 Thus, the total probability of either event occurring is 1/12 + 1/12 = 2/12 = 1/6 Final Answer: E GMAT assassins aren't born, they're made, Rich _________________ Contact Rich at Rich.C@empowergmat.com • FREE GMAT Exam Know how you'd score today for$0

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