A certain manufacturer sells its products to stores in 113

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A certain manufacturer sells its products to stores in 113 different regions worldwide, with an average (arithmetic mean) of 181 stores per region. If last year these stores sold an average of 51,752 units of the manufacturer's product per store, which of the following is closest to the total number of units of manufacturer's products sold worldwide last year?

A. 10^6
B. 10^7
C. 10^8
D. 10^9
E. 10^10

The OA is D.

Number of different regions = 113
Average of stores per region = 181
Average units sold per store = 51752

Total number of units of manufacturer's product sold worldwide last year = 131*181*51752

We should use estimation here
110 * 180 * 50,000
= 198 * 10^2 * 50,000
= 2 * 10^4 * 5* 10^4
= 10 * 10^8
=10^9
Answer D.

Has anyone another strategic approach to solve this PS question? Regards!
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by swerve » Thu May 24, 2018 9:50 am
1. 181 Stores x 113 regions = 20,453

2. 20,453 x 51,752 (I worked this out the long way but the scientific notation is faster)

3. 2 x 10^4 x 5 x 10^4 = 10 x 10^8 (just add exponents since base and exponent is the same)

4. 10^9

Option D. Regadrs!

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by Scott@TargetTestPrep » Thu May 24, 2018 5:03 pm
AAPL wrote:A certain manufacturer sells its products to stores in 113 different regions worldwide, with an average (arithmetic mean) of 181 stores per region. If last year these stores sold an average of 51,752 units of the manufacturer's product per store, which of the following is closest to the total number of units of manufacturer's products sold worldwide last year?

A. 10^6
B. 10^7
C. 10^8
D. 10^9
E. 10^10
We are given that a certain manufacturer sells its products to stores in 113 different regions, with an average (arithmetic mean) of 181 stores per region and 51,752 units per store.

Since we are asked, which of the following is closest to the total number of units of manufacturer's product sold worldwide last year, we can use estimation.

113 ≈ 100

181 ≈ 200

51,752 ≈ 50,000

Thus, the approximate number of units sold worldwide last year was:

100 x 200 x 50,000 = (10^2) x (2 x 10^2) x (5 x 10^4) = 10 x 10^8 = 10^9

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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by deloitte247 » Fri May 25, 2018 12:14 pm
Number of different regions = 113
Average stores per region = 181
Average units sold per store = 51,752
Total number of units of manufacturers product sold worldwide last year =
113 * 181 * 51,752
rounding off the number to the nearest hundred and thousandth (estimation)
$$100\ \cdot\ 200\ \cdot\ 50,000$$
$$\left(1\cdot10^2\right)\ \cdot\ \left(2\ \cdot\ 10^2\right)\ \cdot\ \left(5\ \cdot\ 10^4\right)$$
$$\left(1\ \cdot\ 2\ \cdot\ 5\ \right)\ \cdot\ \left(10^{2+2+4}\right)$$
$$10^1\ \cdot\ 10^8\ $$
$$10^{8+1}\ $$
$$10^9$$
Option D is correct