-
EbrahimHashem
- Junior | Next Rank: 30 Posts
- Posts: 29
- Joined: Mon Mar 09, 2009 6:39 am
Answer should be C.
As 1 gives x = 2 and -3
and 2 gives x = -7 and 2
Combining both we get x = 2
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Featured Course
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
How are you Älgabra"skills? Try this!
Source: Beat The GMAT — Data Sufficiency |
(1) gives us x=0,-3,2EbrahimHashem wrote:What is the value of x ?
(1) x^3 = 6x - x^2
(2) 14x = x^3 + 5x^2
HAVE FUN!
(2) gives us x=0,2,7
from (1) and (2) we get x=0,2
since the question asks what *is* (singular) the value of x, the answer must be (E), since from neither (1) or (2) can we get one single value for x.
(E)
Your answer is correct! but what's wrong with the first answer provided by"kyabe"? is there anything we both are missing?qwe12 wrote:(1) gives us x=0,-3,2EbrahimHashem wrote:What is the value of x ?
(1) x^3 = 6x - x^2
(2) 14x = x^3 + 5x^2
HAVE FUN!
(2) gives us x=0,2,7
from (1) and (2) we get x=0,2
since the question asks what *is* (singular) the value of x, the answer must be (E), since from neither (1) or (2) can we get one single value for x.
(E)
Ebrahim the answer posted by qwe12 should be correct as when I used deduced the solution I cancelled x from LHS and RHS. Now when we cancel X, 0 can be one of the factors. And as said by qwe12 after combining i and ii we are left with two values of x ie 0 and 2. Hence its E. Does that makes sense?EbrahimHashem wrote:Your answer is correct! but what's wrong with the first answer provided by"kyabe"? is there anything we both are missing?qwe12 wrote:(1) gives us x=0,-3,2EbrahimHashem wrote:What is the value of x ?
(1) x^3 = 6x - x^2
(2) 14x = x^3 + 5x^2
HAVE FUN!
(2) gives us x=0,2,7
from (1) and (2) we get x=0,2
since the question asks what *is* (singular) the value of x, the answer must be (E), since from neither (1) or (2) can we get one single value for x.
(E)
From i) The factors are 0,2,-3
From ii) The factors are 0,2,-7
Combining these we get two factors of X ie 0 and 2.
Since we can't say that only one value of x will satisfy both the equations as there are two values 0 and 2. The answer is E
From ii) The factors are 0,2,-7
Combining these we get two factors of X ie 0 and 2.
Since we can't say that only one value of x will satisfy both the equations as there are two values 0 and 2. The answer is E
