How are you Älgabra"skills? Try this!

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What is the value of x ?

(1) x^3 = 6x - x^2
(2) 14x = x^3 + 5x^2



HAVE FUN! :D

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by kyabe » Sat Sep 05, 2009 9:52 am
Answer should be C.

As 1 gives x = 2 and -3

and 2 gives x = -7 and 2

Combining both we get x = 2

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Re: How are you Älgabra"skills? Try this!

by qwe12 » Sun Sep 06, 2009 12:06 am
EbrahimHashem wrote:What is the value of x ?

(1) x^3 = 6x - x^2
(2) 14x = x^3 + 5x^2

HAVE FUN! :D
(1) gives us x=0,-3,2
(2) gives us x=0,2,7

from (1) and (2) we get x=0,2

since the question asks what *is* (singular) the value of x, the answer must be (E), since from neither (1) or (2) can we get one single value for x.

(E)

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qwe12 wrote:
EbrahimHashem wrote:What is the value of x ?

(1) x^3 = 6x - x^2
(2) 14x = x^3 + 5x^2

HAVE FUN! :D
(1) gives us x=0,-3,2
(2) gives us x=0,2,7

from (1) and (2) we get x=0,2

since the question asks what *is* (singular) the value of x, the answer must be (E), since from neither (1) or (2) can we get one single value for x.

(E)
Your answer is correct! but what's wrong with the first answer provided by"kyabe"? is there anything we both are missing?

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Re: How are you Älgabra"skills? Try this!

by kyabe » Sun Sep 06, 2009 12:00 pm
EbrahimHashem wrote:
qwe12 wrote:
EbrahimHashem wrote:What is the value of x ?

(1) x^3 = 6x - x^2
(2) 14x = x^3 + 5x^2

HAVE FUN! :D
(1) gives us x=0,-3,2
(2) gives us x=0,2,7

from (1) and (2) we get x=0,2

since the question asks what *is* (singular) the value of x, the answer must be (E), since from neither (1) or (2) can we get one single value for x.

(E)
Your answer is correct! but what's wrong with the first answer provided by"kyabe"? is there anything we both are missing?
Ebrahim the answer posted by qwe12 should be correct as when I used deduced the solution I cancelled x from LHS and RHS. Now when we cancel X, 0 can be one of the factors. And as said by qwe12 after combining i and ii we are left with two values of x ie 0 and 2. Hence its E. Does that makes sense?

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by EbrahimHashem » Sun Sep 06, 2009 12:47 pm
I'm not sure whether I understand what you are saying :roll: Can you please elaborate on this?

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by kyabe » Sun Sep 06, 2009 12:57 pm
From i) The factors are 0,2,-3
From ii) The factors are 0,2,-7

Combining these we get two factors of X ie 0 and 2.

Since we can't say that only one value of x will satisfy both the equations as there are two values 0 and 2. The answer is E