Hi
I solved it the following way. Is my approach correct? Please comment.
we have 4 options ( 0,1,2,3 employees) for the first office and 1 for the other. Multiply by 2 as we can assign employees to 2nd office first ,in which case 1st office will have only 1 option. 4*1*2=8
A certain company assigns employees to offices in such a way
Hi imane81,
Also, you can try as follow,
Two offices can be filled in two ways when all the three employees will be in the same room or when two employees in one room and one in other room.
Wehn all the three employees will be in the same room = 3C3 * 2! = 2 (2! because any of the rooms can be taken).
When two employees in one room and one in other room = 3C2 * 1C1 * 2! = 6.
Hence total ways = 6 + 2 = 8. Option D.
Regards!
Also, you can try as follow,
Two offices can be filled in two ways when all the three employees will be in the same room or when two employees in one room and one in other room.
Wehn all the three employees will be in the same room = 3C3 * 2! = 2 (2! because any of the rooms can be taken).
When two employees in one room and one in other room = 3C2 * 1C1 * 2! = 6.
Hence total ways = 6 + 2 = 8. Option D.
Regards!
