BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

√[2√63 + 2/(8+3√7)] =

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pmFollowed by: 2 members
Location: Arabian Sea
Thanked: 125 times

by ajith » Tue Feb 09, 2010 1:33 pm
imane81 wrote:Couldn't find the answer for this one... please help, thank you

√[2√63 + 2/(8+3√7)] =

A. 8 + 3√7
B. 4 + 3√7
C. 8
D. 4
E. √7
Please search before you post : https://www.beatthegmat.com/sqrt-2-sqrt- ... 50747.html
Always borrow money from a pessimist, he doesn't expect to be paid back.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Tue Feb 09, 2010 3:45 pm
Thanked: 1 times

by frherndon » Tue Feb 09, 2010 3:46 pm
Easy:
- Reduce the equation then factor out 2^4 (e.g. 2 to the 4th power) in the numerator = (2^4*3S-Root of 7 + 2^7)
- Now reduce by Factoring out 2^4 = 2^4*(3*S-Root 7 +2^3) / (3*S-Root of 7 +2^3)
- Cancel like terms from the numerator and demoninator [e.g. (3*S-Root of 7 + 2^3)]
- The residual term = 2^4
- Take the square root of 2^4 = S-Root of 16 = 4

ANSWER - D
If anyone needs help solving down to above from the original problem feel free to email me then I'll email you the scanned answer. This problem is difficult to explain with the characters on the typical typing keyboard because it does not have a square root symbol.

I will say this "When u come to a cross roads in a radical problem - FACTOR", which is the key to answering this problem.
Last edited by frherndon on Tue Feb 09, 2010 3:58 pm, edited 2 times in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1