A car travels from point A to B. The average speed of the

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A car travels from point A to point B. The average speed of the car is 60 miles/hr and it travels the first half of the trip at a speed of 90 mi/hr. What is the speed of the car in the second half of the trip?

A. 30
B. 45
C. 60
D. 75
E. 90

The OA is B.

Please, can anyone explain this PS question? I tried to solve it but I can't get the correct answer. I need help. Thanks.
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by [email protected] » Fri Jun 01, 2018 9:44 am
Hi swerve,

We're told that a car travels from point A to point B. The average speed of the car is 60 miles/hr and it travels the first half of the distance at a speed of 90 mi/hr. We're asked for the speed of the car in the second half of the trip. This question can be solved by TESTing VALUES.

IF.... Total Distance = 180 miles....
First half of the trip = 90 miles at 90 miles/hour = 90/90 = 1 hour

The entire trip = 180 miles at 60 miles/hour = 180/60 = 3 hours

Thus, the second half of the trip would take 3-1 = 2 hours....
Second half of the trip = 90 miles in 2 hours = 90/2 = 45 miles/hour

Final Answer: B

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by Brent@GMATPrepNow » Fri Jun 01, 2018 9:55 am
swerve wrote:A car travels from point A to point B. The average speed of the car is 60 miles/hr and it travels the first half of the trip at a speed of 90 mi/hr. What is the speed of the car in the second half of the trip?

A. 30
B. 45
C. 60
D. 75
E. 90
There's a bit of ambiguity here.

If the first half of the trip is spent at one speed, and the second half is spent at another speed, are we referring to half the total DISTANCE, or half the total TIME.
For example, if it takes 10 hours to drive 200 miles, some people might refer to the first half of the trip as being the first 5 hours of driving. Others might refer to the first half of the trip as being the first 100 miles traveled.

That said, the official answer informs us that we're talking about half the DISTANCE.

To make things easier for us, let's assign a NICE VALUE to the TOTAL distance. That is, a number that works well with 60 and 90

Let's say the TOTAL distance is 540 miles.
This means the car traveled 270 miles at 90 mph, and the car traveled 270 miles at x mph.
It also means the car traveled the total 540 miles at an average speed of 60 mph

Let's start with a word equation: time spent driving 90 mph + time spent driving x mph = TOTAL time of trip
Time = distance/speed
So, we now get: 270/90 + 270/x = 540/60
Simplify to get: 3 + 270/x = 9
This means that 270/x = 6
Multiply both sides by x to get: 270 = 6x
Solve: x = 45 (mph)

Answer: B

Cheers,
Brent
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by Jeff@TargetTestPrep » Mon Jun 18, 2018 11:02 am
swerve wrote:A car travels from point A to point B. The average speed of the car is 60 miles/hr and it travels the first half of the trip at a speed of 90 mi/hr. What is the speed of the car in the second half of the trip?

A. 30
B. 45
C. 60
D. 75
E. 90
We can use the formula:

average = total distance/total time

Let's denote the total distance by d and the unknown speed of the car in the second half of the trip by r.

60 = d/[(d/2)/90 + (d/2)/r)]

60 = d/[d/180 + d/2r]

60[d/180 + d/2r] = d

d/3 + 30d/r = d

1/3 + 30/r = 1

30/r = 2/3

2r = 90

r = 45

Answer: B

Jeffrey Miller
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