BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

A box measuring 54 inches long by 36 inches wide...

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Moderator
Posts: 2710
Joined: Sun Oct 29, 2017 2:08 pmFollowed by: 2 members
by AAPL » Sun Jan 14, 2018 7:47 am
A box measuring 54 incches by long 36 inches wide by 12 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest numbre of cubes that can accomplish this objective?

A. 17
B. 18
C. 54
D. 108
E. 864

The OA is D.

I don't have clear this PS question, I should find the maximum common divisor of the 3 dimensions of the box, right? I appreciate if any expert explain it for me. Thank you so much.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pmFollowed by: 511 members
Location: Palo Alto, CA
Thanked: 2867 times
GMAT Score:800

by [email protected] » Sun Jan 14, 2018 10:38 am
Hi AAPL,

We're told that a box measuring 54 inches by 36 inches by 12 inches is to be filled entirely with identical CUBES and NO space is to be left unfilled. We're asked for the SMALLEST number of cubes that can accomplish this objective.

Since the length, width and height of a cube are the SAME - and we have to fill ALL of the space in the box - we need the length of the cube to be a factor of 54, 36 and 12 (and since we want the LEAST number of cubes possible, we need the greatest common factor of all three numbers). In this case, that would be 6.

6 divides evenly into 54 (9 times), 36 (6 times) and 12 (2 times), so the number of 6x6x6 cubes that will fill this box is (9)(6)(2) = 108 cubes

Final Answer: D

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8211
Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members
Location: Los Angeles, CA
Thanked: 43 times

by Scott@TargetTestPrep » Mon Aug 05, 2019 4:15 pm
AAPL wrote:A box measuring 54 incches by long 36 inches wide by 12 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest numbre of cubes that can accomplish this objective?

A. 17
B. 18
C. 54
D. 108
E. 864
Since we want to fit the smallest number of cubes in the box, we want each cube to be as large as possible. Since the greatest common factor of 54, 36 and 12 is 6, the largest cube is 6 x 6 x 6. Therefore, the smallest number of cubes we can fit in the box is:

(54 x 36 x 12)/(6 x 6 x 6) = 9 x 6 x 2 = 108

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1