BTGmoderatorDC wrote:A bowl contains equal numbers of red, orange, green, blue, and yellow candies. Kaz eats all of the green candies and half of the orange ones. Next, he eats half of the remaining pieces of each color. Finally, he eats red and yellow candies in equal proportions until the total number of remaining candies of all colors equals 15% of the original number. What percent of the red candies remain?
A. 0%
B. 5%
C. 10%
D.15%
E. 20%
Let R=O=G=B=Y=20, for a total of 100 marbles.
Kaz eats all of the green candies and half of the orange ones.
R=20, O=10, G=0, B=20, Y=20
He eats half of the remaining pieces of each color.
R=10, O=5, G=0, B=10, Y=10
He eats red and yellow candies in equal proportions until the total number of remaining candies of all colors equals 15% of the original number.
Since only 15 of the original 100 candies must remain, Kaz must eat the 10 remaining red and 10 remaining yellow candies, leaving only O=5 and B=10:
R=0, O=5, G=0, B=10, Y=0
What percent of the red candies remain?
(new R)/(original R) = 0/20 = 0%
The correct answer is
A.
Last edited by GMATGuruNY on Sat Jul 20, 2019 12:03 pm, edited 1 time in total.
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