odd integers

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odd integers

by finance » Tue Aug 09, 2011 6:28 am
How many odd integers are there greater than integer X and less than integer Y??
1) There are 12 even integers between X & Y
2) There are 24 integers between X and Y?
Source: — Data Sufficiency |

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by GmatKiss » Tue Aug 09, 2011 6:35 am
IMO:C

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by Gurpinder » Tue Aug 09, 2011 10:23 am
finance wrote:How many odd integers are there greater than integer X and less than integer Y??
1) There are 12 even integers between X & Y
2) There are 24 integers between X and Y?
Q: x < odd integers < y

1) We can't say that there are 12 odd integers because (1) we don't know what the END digits of this set are (2) we don't know whether this is a consecutive set or even the increment

2) Again same as above.

Together:
x < 24 integers < y
from (1) we know that there are 12 even, that must mean that there are 12 odd integers.

hence (c)
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by finance » Tue Aug 09, 2011 12:37 pm
I thought exactly like you did, but unfortunately it is B:((

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by HeintzC2 » Tue Aug 09, 2011 1:21 pm
Choice 1), if there are 12 even integers, starting on an odd integer vs. starting on an even integer (i.e. the first number in the sequence is 1 vs. 2) impacts how many odd integers you will count. insufficient.

Using choice 2), we know there are 24 integers between x & y. automatically half of those integers must be odd. Regardless if the first integer is odd or even, you will pass 12 odd and 12 even integers. Sufficient.

Answer is B
Gurpinder wrote:
finance wrote:How many odd integers are there greater than integer X and less than integer Y??
1) There are 12 even integers between X & Y
2) There are 24 integers between X and Y?
Q: x < odd integers < y

1) We can't say that there are 12 odd integers because (1) we don't know what the END digits of this set are (2) we don't know whether this is a consecutive set or even the increment

2) Again same as above.

Together:
x < 24 integers < y
from (1) we know that there are 12 even, that must mean that there are 12 odd integers.

hence (c)

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by gmatboost » Tue Aug 09, 2011 10:28 pm
To see why the answer is B, let's go through the same question with a slight change:

How many odd integers are there greater than integer X and less than integer Y?
1) There are 2 even integers between X & Y
2) There are 4 integers between X and Y?

Statement 1
Could be X = 3, Y = 7 (4 and 6 in between) -> only 5 is in between
Could be X = 2, Y = 8 (4 and 6 in between) -> 3, 5, 7 all in between
[spoiler]Insuff.
[/spoiler]
Statement 2

Could be X = 3, Y = 8 (4-7 in between) -> 5, 7 in between
Could be X = 2, Y = 7 (3-6 in between) -> 3, 5 in between
[spoiler]This doesn't prove sufficiency, but it shows that in each case there are 2. More broadly, it is correct to say that half of the 4 integers must be odd, so we know it is 2.[/spoiler]
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