To see why the answer is B, let's go through the same question with a slight change:
How many odd integers are there greater than integer X and less than integer Y?
1) There are 2 even integers between X & Y
2) There are 4 integers between X and Y?
Statement 1
Could be X = 3, Y = 7 (4 and 6 in between) -> only 5 is in between
Could be X = 2, Y = 8 (4 and 6 in between) -> 3, 5, 7 all in between
[spoiler]Insuff.
[/spoiler]
Statement 2
Could be X = 3, Y = 8 (4-7 in between) -> 5, 7 in between
Could be X = 2, Y = 7 (3-6 in between) -> 3, 5 in between
[spoiler]This doesn't prove sufficiency, but it shows that in each case there are 2. More broadly, it is correct to say that half of the 4 integers must be odd, so we know it is 2.[/spoiler]
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