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by rarns » Mon Jun 13, 2011 7:01 am
5^2 + x^2 = root61^2

24 + x = 61

x = 36

sides of tri = 5,6

from that info we can derive the area as 21.
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by Frankenstein » Mon Jun 13, 2011 7:01 am
Hi,
Let the length of the base be x. Draw a horizontal line 1 unit above the base to form a right angled triangle.
Applying Pythagoras theorem, x^2 + 5^2 = 61 => x2 = 36. So, x= 6
Area of trapezium is (1/2)*6*(1+6) = 21 sq.units
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by MBA.Aspirant » Mon Jun 13, 2011 7:23 am
I thought root 61 is the length of the base, not the hypotenuse?

"Given that the length to the top is root 61"
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by MBA.Aspirant » Mon Jun 13, 2011 3:09 pm
MBA.Aspirant wrote:I thought root 61 is the length of the base, not the hypotenuse?

"Given that the length to the top is root 61"
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