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by tom4lax » Sat Jul 11, 2009 2:26 pm
I'm stuck at (27x^7/3 - 14x^5/2) / (3x^2)

What can be done to simplify further?
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by shibal » Sun Jul 12, 2009 10:33 am
i really don't know, i got this exercise at a peterson's book.

it gives a weird way to solve the x^7 and the others..... let's wait for the other's opinion...
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by real2008 » Sun Jul 12, 2009 10:47 am
i find the answer to be ((3x)^1/3)-((14x)^1/2)
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by shibal » Sun Jul 12, 2009 10:53 am
how u simplified the xs?
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by real2008 » Sun Jul 12, 2009 11:08 am
shibal wrote:how u simplified the xs?
((81x^7)^1/3)/((9x^4)^1/2)) - ((126x^5)^1/2)/((27x^6)^1/3))
= [{(3^4)*(x^7)}^1/3]/[{(3^2)*(x^4)}^1/2]-[{(3^2)*2*7*(x^5))}^1/2]/[{(3^3)*(x^6)}^1/3]

= [(3^4/3)*(x^7/3)]/[3*(x^2)]-[3*(2^1/2)*(7^1/2)*(x^5/2)]/[3*(x^2)]

= (3^1/3)*(x^1/3)-(2^1/2)*(7^1/2)*(x^1/2)

=(3x)^1/3 - (14x)^1/2
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