Target Test Prep's 2024 GMAT Focus Edition prep is discounted for the BTG community!

Redeem
Target Test Prep
5-Day Free Trial
5-day free, full-access trial TTP

Available with Beat the GMAT members only code

MORE DETAILS
Target Test Prep
Magoosh
Magoosh
Study with Magoosh GMAT prep

Available with Beat the GMAT members only code

MORE DETAILS
Magoosh

simplify

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 345
Joined: Wed Mar 18, 2009 6:53 pm
Location: Sao Paulo-Brazil
Thanked: 12 times
GMAT Score:660

simplify

by shibal » Sat Jul 11, 2009 2:13 pm
((81x^7)^1/3)/((9x^4)^1/2)) - ((126x^5)^1/2)/((27x^6)^1/3))
Top
Master | Next Rank: 500 Posts
Posts: 175
Joined: Mon Feb 09, 2009 3:57 pm
Thanked: 4 times

by tom4lax » Sat Jul 11, 2009 2:26 pm
I'm stuck at (27x^7/3 - 14x^5/2) / (3x^2)

What can be done to simplify further?
Top
Master | Next Rank: 500 Posts
Posts: 345
Joined: Wed Mar 18, 2009 6:53 pm
Location: Sao Paulo-Brazil
Thanked: 12 times
GMAT Score:660

by shibal » Sun Jul 12, 2009 10:33 am
i really don't know, i got this exercise at a peterson's book.

it gives a weird way to solve the x^7 and the others..... let's wait for the other's opinion...
Top
Legendary Member
Posts: 527
Joined: Thu May 01, 2008 12:06 am
Thanked: 7 times

by real2008 » Sun Jul 12, 2009 10:47 am
i find the answer to be ((3x)^1/3)-((14x)^1/2)
Top
Master | Next Rank: 500 Posts
Posts: 345
Joined: Wed Mar 18, 2009 6:53 pm
Location: Sao Paulo-Brazil
Thanked: 12 times
GMAT Score:660

by shibal » Sun Jul 12, 2009 10:53 am
how u simplified the xs?
Top
Legendary Member
Posts: 527
Joined: Thu May 01, 2008 12:06 am
Thanked: 7 times

by real2008 » Sun Jul 12, 2009 11:08 am
shibal wrote:how u simplified the xs?
((81x^7)^1/3)/((9x^4)^1/2)) - ((126x^5)^1/2)/((27x^6)^1/3))
= [{(3^4)*(x^7)}^1/3]/[{(3^2)*(x^4)}^1/2]-[{(3^2)*2*7*(x^5))}^1/2]/[{(3^3)*(x^6)}^1/3]

= [(3^4/3)*(x^7/3)]/[3*(x^2)]-[3*(2^1/2)*(7^1/2)*(x^5/2)]/[3*(x^2)]

= (3^1/3)*(x^1/3)-(2^1/2)*(7^1/2)*(x^1/2)

=(3x)^1/3 - (14x)^1/2
Top
Post new topic Post Reply
• Page 1 of 1