BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Local Trade show problem

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 182
Joined: Sun Aug 02, 2009 7:19 pm
Thanked: 18 times
GMAT Score:680

Local Trade show problem

by sanjana » Sat Oct 03, 2009 10:10 pm
During a 6 day local trade show,the least number of people registered in a single day was 80.Was the Avg(arithemetic mean) number of ppl registered per day for the 6 days greater than 90?

a)For the 4 days with the greatest number of ppl registered,the avg(arithemetic mean) number registered per day was 100.

b)For the 3 days with the smallest number of ppl registered,the avg number registered per day was 85
Top
Source: — Data Sufficiency |
Junior | Next Rank: 30 Posts
Posts: 13
Joined: Mon Feb 25, 2008 12:16 am
Location: Hyd
GMAT Score:650

by catchyblues » Sun Oct 04, 2009 7:30 am
IMO A

1) Out of 6 days, 4 days had avg number registered per day = 100

That makes 400 for 4 days. Adding 80 to will give us 480. Even by considering the 6th day as 80 or 81, the average for 6 days will be greater that 90.

2)For the 3 days with the smallest number of ppl registered,the avg number registered per day was 85.

So for 3 days (including the 80 from the main statement), the today for 3 days is 265. We don't have any information about the other 3 days. Even if we assume a minimum of 86 for each of the 3 days, the avg will be less than 90. If we assume 100 for each of the 3 days, the avg will be > 90. Hence we can't solve using (2).
Top
Master | Next Rank: 500 Posts
Posts: 182
Joined: Sun Aug 02, 2009 7:19 pm
Thanked: 18 times
GMAT Score:680

by sanjana » Sun Oct 04, 2009 8:12 pm
Thanks!
The OA is A.
Top
Post new topic Post Reply
• Page 1 of 1