0 <2x + y <50, -50 <x + 2y <0, ask which of the following must be true ( you can select more than 1 that is right?
I. x> 0
II. Y> 0
III. X> y
I. x> 0
II. Y> 0
III. X> y
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From the inequality 0 < 2x + y < 50, we get that the sum of two x and one y is positive (0 < 2x + y). When one x is replaced with a y, the inequality becomes -50 < x + 2y < 0. We see that now the sum of two y and one x is negative (x + 2y < 0). This implies that x is positive and y is negative; and x > y.mihai9 wrote:0 <2x + y <50, -50 <x + 2y <0, ask which of the following must be true ( you can select more than 1 that is right?
I. x> 0
II. Y> 0
III. X> y
Inequalities can be LINKED TOGETHER.mihai9 wrote:0 <2x + y <50, -50 <x + 2y <0, ask which of the following must be true ( you can select more than 1 that is right?
I. x> 0
II. Y> 0
III. X> y
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