x,y,z are integers such that 0<x<y<z. Is X < 6?
1) z> 10
2) x + y + z = 18
OA given is B but I feel it should be E
1) z> 10
2) x + y + z = 18
OA given is B but I feel it should be E
From 1
we cannot conclude anything
From2
Since 0<x<y<z
x+y+z=3x+k..where k is non zero integer
so 3x+k=18..now the maximum possible integer value of x is 5 which will satisfy this equation
hence X<6..sufficient
Ans B
