x,y,z are integers such that 0<x<y<z. Is X < 6?
1) z> 10
2) x + y + z = 18
OA given is B but I feel it should be E
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72) Is x < 6
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liferocks
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From 1
we cannot conclude anything
From2
Since 0<x<y<z
x+y+z=3x+k..where k is non zero integer
so 3x+k=18..now the maximum possible integer value of x is 5 which will satisfy this equation
hence X<6..sufficient
Ans B
we cannot conclude anything
From2
Since 0<x<y<z
x+y+z=3x+k..where k is non zero integer
so 3x+k=18..now the maximum possible integer value of x is 5 which will satisfy this equation
hence X<6..sufficient
Ans B
"If you don't know where you are going, any road will get you there."
Lewis Carroll
Lewis Carroll
from 1:
we know
x<y<=10
x can be <6 or =6 or >6
Not Sufficient
from 2:
x + y + z = 18
If x takes any value >=6 then y+z<=12 So either y or z will become less than or equal to x. that can't be since x<y<z
so, x<6
answer B
we know
x<y<=10
x can be <6 or =6 or >6
Not Sufficient
from 2:
x + y + z = 18
If x takes any value >=6 then y+z<=12 So either y or z will become less than or equal to x. that can't be since x<y<z
so, x<6
answer B
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