imo A
1,is sufficient alone but 2is not sufficient
is x > y?
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Source: Beat The GMAT — Data Sufficiency |
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pradeepkaushal9518
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gmatmachoman
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St 1 :neoreaves wrote:If xy ≠0, is x > y?
(1) 4x = 3y
(2) |y - x| = x - y
x= 0.75 Y
X can greater or lesser than Y depending on Y. If Y is positive x is less than Y. If Y is negative then X can greater than Y.
Inconsistent- Insufficient.
St 2:
|y - x| = x - y
y-x =x-y
: 2y =2x
y=x
from this we can answer whether x>y as we have deduced x=y. The answer may be a YES or a NO. But it is definite.
Going further for nailing it, try some plugging in values for X & Y with X>Y & X<Y
Case 1: X >Y
Let X =2 Y= 1
|1-2| =2-1
|-1| = 1
1=1
YES X > Y
Case 2: X= 1 Y=2
|2-1| = 1-2
|1| = -1
LHS NOT equal to RHS . So X is not less than Y.
St 2 is sufficient to say X >Y
Pick B
Plz correct me if my method is wrong.
xy≠0. So, x≠0, y≠0neoreaves wrote:If xy ≠0, is x > y?
(1) 4x = 3y
(2) |y - x| = x - y
from 1:
x=3y/4
If y is negative, x>y
If y is positive, x<y
Insufficient.
from 2:
|y - x| = x - y
if y>x, y-x=x-y, y=x, but y>x. So, this can't be.
if x>y, y-x=-(x-y)=y-x So, this is possible.
if x=y, y-x=x-y, So, again this is possible.
Insufficient
Combining 1 and 2:
For x and y to satisfy both 1 and 2, x≠y, and x>y
IMO answer C
"Choose to chance the rapids and dance the tides"
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gmatmachoman
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Seer bhai,
can u explain using some plugged values?
can u explain using some plugged values?
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harshavardhanc
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one question to all :
if I say, |Z| = ?
it will be Z if Z is positive.
and it will be -Z if Z is negative.
now, just put y-x in place of Z and look at statement 2 again.
does anyone want to change his answer?
if I say, |Z| = ?
it will be Z if Z is positive.
and it will be -Z if Z is negative.
now, just put y-x in place of Z and look at statement 2 again.
does anyone want to change his answer?
Regards,
Harsha
Harsha
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gmatmachoman
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harsha bhai...harshavardhanc wrote:one question to all :
if I say, |Z| = ?
it will be Z if Z is positive.
and it will be -Z if Z is negative.
now, just put y-x in place of Z and look at statement 2 again.
does anyone want to change his answer?
plz plz no surprise..i want toc ur answer, ahahhaha!!
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harshavardhanc
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macho Anna,gmatmachoman wrote:harsha bhai...harshavardhanc wrote:one question to all :
if I say, |Z| = ?
it will be Z if Z is positive.
and it will be -Z if Z is negative.
now, just put y-x in place of Z and look at statement 2 again.
does anyone want to change his answer?
plz plz no surprise..i want toc ur answer, ahahhaha!!
all I'm saying is if you put y-x in place of Z and look at st2 again, you'll find that
y-x should be -ve to satisfy it.
implies, y-x < 0 OR y<x. Sufficient to answer the question.
hence, B 
Regards,
Harsha
Harsha
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gmatmachoman
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Harsha..that was awesome...!! B wins!!harshavardhanc wrote:macho Anna,gmatmachoman wrote:harsha bhai...harshavardhanc wrote:one question to all :
if I say, |Z| = ?
it will be Z if Z is positive.
and it will be -Z if Z is negative.
now, just put y-x in place of Z and look at statement 2 again.
does anyone want to change his answer?
plz plz no surprise..i want toc ur answer, ahahhaha!!
all I'm saying is if you put y-x in place of Z and look at st2 again, you'll find that
y-x should be -ve to satisfy it.
implies, y-x < 0 OR y<x. Sufficient to answer the question.
@Harsha,
you are right. But aren't we ignoring the possibility that x can be equal to y also.
If x=y, statement 2 still holds true.
@gmatmachoman
here are the numbers to plug in
statement 2:
x,y,y-x,|y-x|,x-y
-3,-2,1,1,-1 -fails
-3,-4,-1,1,1 - passes x>y
-3,2,5,5,-5 - fails
-3,-3,0,0,0 - passes x=y
3,4,1,1,-1 - fails
3,2,-1,1,1 - passes x>y
3,-4,-7,-7,7 - passes x>y
So, x is either greater or equal to y to satisfy the condition given in statement 2[/list]
you are right. But aren't we ignoring the possibility that x can be equal to y also.
If x=y, statement 2 still holds true.
@gmatmachoman
here are the numbers to plug in
statement 2:
x,y,y-x,|y-x|,x-y
-3,-2,1,1,-1 -fails
-3,-4,-1,1,1 - passes x>y
-3,2,5,5,-5 - fails
-3,-3,0,0,0 - passes x=y
3,4,1,1,-1 - fails
3,2,-1,1,1 - passes x>y
3,-4,-7,-7,7 - passes x>y
So, x is either greater or equal to y to satisfy the condition given in statement 2[/list]
"Choose to chance the rapids and dance the tides"
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harshavardhanc
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agree! thanks mate!iamseer wrote:@Harsha,
you are right. But aren't we ignoring the possibility that x can be equal to y also.
If x=y, statement 2 still holds true.
@gmatmachoman
here are the numbers to plug in
statement 2:
x,y,y-x,|y-x|,x-y
-3,-2,1,1,-1 -fails
-3,-4,-1,1,1 - passes x>y
-3,2,5,5,-5 - fails
-3,-3,0,0,0 - passes x=y
3,4,1,1,-1 - fails
3,2,-1,1,1 - passes x>y
3,-4,-7,-7,7 - passes x>y
So, x is either greater or equal to y to satisfy the condition given in statement 2[/list]
Regards,
Harsha
Harsha
