- wayofjungle
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The most common way to solve this question is to set the bases on each side of the equation equal to each other so that a separate equation can be written with the exponents equal to each other. My question is why we can't use a fraction as base? I ask this question after solving Statement 2 on Q166 of DS OG which states:
(1/10)^(n-1) < 0.1
If we rephrase with fractions as base for exponents we get:
(1/10)^(n-1) < (1/10)^1, so n-1 < 1, and n < 2
If we rephrase with the base 10 (non-fraction) we get:
(10^-1)^(n-1) < (10^-1), so (10)^(-n+1) < (10)^(-1), and 1-n < -1 or n > 2 (which is the correct solution given by the book)
As you can see the inequalities are opposite, so why do we need to have the base as an integer before we can set exponents equal to one another?
(1/10)^(n-1) < 0.1
If we rephrase with fractions as base for exponents we get:
(1/10)^(n-1) < (1/10)^1, so n-1 < 1, and n < 2
If we rephrase with the base 10 (non-fraction) we get:
(10^-1)^(n-1) < (10^-1), so (10)^(-n+1) < (10)^(-1), and 1-n < -1 or n > 2 (which is the correct solution given by the book)
As you can see the inequalities are opposite, so why do we need to have the base as an integer before we can set exponents equal to one another?

















