200 and 300 (both inclusive)

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by pavan.mpv » Thu Feb 02, 2012 7:57 am
marcusking wrote:divisble by 2 = 1+100/2 =51
divisble by 3 =1+99/3 = 34
divisble by 5 = 1+100/5 = 21

divisble by 6 (both 2 and 3)= 1+94/6 =16 -- ( I didn't understand this part... to find number of integers from 200-300 (inclusive) that are divisible by 6, (300-200)/6+1 = 16+1=17. Can someone tell me where I am wrong?)
divisble by 15 (both 3 and 5)= 1+90/15 =7
divisble by 10 (both 2 and 5)= 1+100/10 =11
divisble by 30 (both 2,3 and 5)= 1+90/30 =4


Nos. divisble by 2/3/5 = 51+34+21 - (16+7+11)+4 = 76

Anser = 101-76= 25
Bingo I got the same. Well done.[/quote]

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by avidanuj » Tue Oct 06, 2015 12:01 am
1+94/6= 16 ??
What math is this ?
It should be 1+96/6=17

And thus the final answer is 26 which is not in the option.