Ans is C - 30
Let length be a and width be b
Given - ab =8b
Thus, a=8
Thus, AB =8
Distance from centre to AB is 3. Let this line drawn from X (centre of circle) to AB meet AB at E. Thus, XE = 3
As X is the centre, XE will be perpendicular bisector to AB. Thus, EB = 4
Triangle EBX is a right angled triangles with one side =3 and other =4. Thus, the third side XB, which is the radius of the circle (because X is centre and B is a point on the circle) = 5 (Pythagoras theorem)
Thus, circumference = 2*3.14*5 = 31.4
option C is the closest approximation of 31.4
Rectangle ABCD is inscribed in a circle with center X.
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Since the area of the rectangle is eight times its width, the length of the rectangle (AB or CD) is 8. Since the distance from X to side AB is 3, the distance from X to side CD is also 3. Therefore, AD or BC, that is, the width of the rectangle is 6. By the Pythagorean theorem, we have:
AC^2 = AB^2 + BC^2
AC^2 = 8^2 + 6^2
AC^2 = 100
AC = 10
Since AC is also the diameter of the circle, the circumference of the circle is AC x π, or 10π. Since π is approximately 3, the circumference is approximately 30.
Answer: C
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