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Source: — Data Sufficiency |
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by liferocks » Sun May 02, 2010 5:34 am
since x is a perfect square,a,b,c and d all has to be even if p,q,r,s are distinct

either From 1 or 2 we cannot conclude whether a,b,c and d are all even hence neither condition is sufficient alone
combining,
since 18 is a factor of ab ,if both a and b are even 4 has to be another factor of ab but from 2 it is not possible hence one of a and b is odd
similarly one of c and d is odd

hence p,q,r,s are not distinct

Ans option C
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by gmatmachoman » Sun May 02, 2010 6:10 am
Not really LR bhai!!

Try once more!
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by liferocks » Sun May 02, 2010 6:44 am
oopps...bad miss

if 4 is not a factor of ab or cd then atleast one of them has to be odd..we can say from 2 itself that p,q,r,s are not distinct..ans will be B

thanks for pointing out.

btw ..u cannot tell me bhai..sis will be more appropriate :)
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by gmatmachoman » Sun May 02, 2010 7:15 am
liferocks wrote:oopps...bad miss

if 4 is not a factor of ab or cd then atleast one of them has to be odd..we can say from 2 itself that p,q,r,s are not distinct..ans will be B

thanks for pointing out.

btw ..u cannot tell me bhai..sis will be more appropriate :)
U nailed that...OA : B...

Sorry for that confusion!!
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