X=1/11+1/12+1/13+......+1/20 , what's the value of X ?
How can we quckly approximate the value for such questions?
How can we quckly approximate the value for such questions?
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You can only apply this rule if you have a set of consecutive numbers, which is not the case with the fractions in this question. Raising the denominator by 1 does not create an equidistant (i.e. a constant distance between each pair of terms) set.Ashish8 wrote:Sum = Average * # items
Average of a 10 number set is the average of digits 5 and digit 6.
Average = (1/15 + 1/16)/2 = (32/240)/2 = (16/240)
Sum = (16/240) * 10 = 16/24 = 2/3

i think if difference in answer choices not much (which is in this type of question) then the appoximation of number will make a huge difference in answer......kuntalkkc wrote: 11.20=220
12.19=228
13.18=234
14.17=238
15.16=240
...Please note no need to calculate these multiplication...i have just shown here for symmetry..
now little bit approx for quick calculation
1st deno is 220 and last deno is 240,so for nearly approx we can take 230).
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