Can anyone do this?

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givemeanid: Master | Next Rank: 500 Posts; Posts: 277; Joined: Sun Jun 17, 2007 2:51 pmFollowed by: 1 member; Location: New York, NY; Thanked: 6 times

by givemeanid » Mon Sep 03, 2007 9:37 am

10X/100 - 8Y/100 = 56
5X - 4Y = 2800

X+Y = 2000 => X = 2000 - Y
5(2000 - Y) - 4Y = 2800
Y = 800

So It Goes

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Source: Beat The GMAT — Problem Solving | Mon Sep 03, 2007 9:37 am

jaspreet.sharma: Junior | Next Rank: 30 Posts; Posts: 24; Joined: Wed Aug 22, 2007 4:49 pm; Thanked: 3 times

Re: Can anyone do this?

by jaspreet.sharma » Mon Sep 03, 2007 11:20 pm

aditya33 wrote:If X dollar is invested @ 10 percent for one year nad Y dollars is invested at 8 percent for one year,the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56.If the dollar 2000 is the total amount invested,how much is invested at 8 percent?

1-280
2:- 800
3:-892
4:-1108
5:-1200 (all figures are in dollars).

I did it in a complex way.Can anyone pls do it in a simple method.
Thnaks.

ATQ
(10*x)/100 – [(2000-x)*8]/ 100 = 56

Solving this eqn

We will Get x= 1200

So ans = 2000-1200 = $ 800

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