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100 < n <200

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Source: — Data Sufficiency |
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IMO

by kc_raj » Sat May 23, 2009 3:10 pm
IMO C

because 36*3, 36*4, 36*5 are betn 100, and 200
and 3, 5 are odd when divided by 36

also 2nd statement, 45*3, 45*4 are options so
3, 4 of which only 4 is even

so combined 36x3, 45x4 =180=n,

C is the answer
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by raleigh » Sat May 23, 2009 7:14 pm
From kc's argument, (2) is sufficient.

n/45 is even implies that n = 45 * 4 = 180 so you know the value of n.

Since (1) is insufficient, the correct answer is B.
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Re: 100 < n <200

by Vemuri » Sat May 23, 2009 7:23 pm
nehakhas1 wrote:If n is an integer and 100 < n <200, what is the value of n?
(1) n/36 is an odd integer.
(2) n/45 is an even integer.

Correct ans C
Please check the OA.

Stmt1: If n/36 is an odd integer, then n=108 or 180. Insufficient.
Stmt2: If 4/45 is an even integer, then the only possible value of n is 180. Sufficient.

IMO B should be the answer.
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Re: 100 < n <200

by Brent@GMATPrepNow » Sun May 24, 2009 8:08 am
Vemuri wrote:
nehakhas1 wrote:If n is an integer and 100 < n <200, what is the value of n?
(1) n/36 is an odd integer.
(2) n/45 is an even integer.

Correct ans C
Please check the OA.

Stmt1: If n/36 is an odd integer, then n=108 or 180. Insufficient.
Stmt2: If 4/45 is an even integer, then the only possible value of n is 180. Sufficient.

IMO B should be the answer.
I have to agree with Vemuri on this one.
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