10^50-74
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prindaroy
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The answer is C.
10 ^ 50 = 51 digits, i.e 10^2 = 100 = 3 digits, 10^3 = 1000 = 4 digits, etc...
so 10.........-74 = 999999........26 with 50 digits in total. So now, 2+6+(9*48)
= 440
10 ^ 50 = 51 digits, i.e 10^2 = 100 = 3 digits, 10^3 = 1000 = 4 digits, etc...
so 10.........-74 = 999999........26 with 50 digits in total. So now, 2+6+(9*48)
= 440
- gmat740
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Can you explain the step marked with Bold.prindaroy wrote:The answer is C.
10 ^ 50 = 51 digits, i.e 10^2 = 100 = 3 digits, 10^3 = 1000 = 4 digits, etc...
so 10.........-74 = 999999........26 with 50 digits in total. So now, 2+6+(9*48)
= 440
- Stuart@KaplanGMAT
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The last two digits are 2 and 6.gmat740 wrote:Can you explain the step marked with Bold.prindaroy wrote:The answer is C.
10 ^ 50 = 51 digits, i.e 10^2 = 100 = 3 digits, 10^3 = 1000 = 4 digits, etc...
so 10.........-74 = 999999........26 with 50 digits in total. So now, 2+6+(9*48)
= 440
The first 48 digits are 9.
So when we sum all the digits, we get 48 9s, one 2 and one 6 to gives us 48*9 + 2 + 6

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
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