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Easy BUT!!!! OG 12 problem!

Expert replies
by soniadiana2011 » Thu May 31, 2012 10:26 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

A carpenter constructed a rectangular sandbox with a
capacity of 10 cubic feet. If the carpenter were to
make a similar sandbox twice as long, twice as wide,
and twice as high as the fi rst sandbox, what would be
the capacity, in cubic feet, of the second sandbox?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100

Please explain me the answer!
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Source: — Problem Solving |

by Anurag@Gurome » Thu May 31, 2012 11:01 am
soniadiana2011 wrote:A carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter were to make a similar sandbox twice as long, twice as wide, and twice as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox?
Say, the first sandbox is a feet long, b feet wide, and c feet high.
Hence, volume of the first sandbox = abc = 10 cubic feet

Now, the second sandbox is 2a feet long, 2b feet wide, and 2c feet high.
Hence, volume of the second sandbox = (2a)*(2b)*(2c) = 8abc = 8*10 cubic feet = 80 cubic feet

The correct answer is D.
Anurag Mairal, Ph.D., MBA
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by aneesh.kg » Thu May 31, 2012 11:04 am
soniadiana2011 wrote:A carpenter constructed a rectangular sandbox with a
capacity of 10 cubic feet. If the carpenter were to
make a similar sandbox twice as long, twice as wide,
and twice as high as the fi rst sandbox, what would be
the capacity, in cubic feet, of the second sandbox?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100

Please explain me the answer!
If the edges of the initial box are a, b and c long, then
Volume = (a)(b)(c) = 10

If each of the dimensions is made twice, then the new lengths of the edges are 2a, 2b and 2c.
New Volume = (2a)(2b)(2c) = 8abc
Since abc = 10,
New Volume = 8*10 = 80 cubic feet

[spoiler](D)[/spoiler] is the answer.
Aneesh Bangia
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by [email protected] » Sat Feb 24, 2018 12:46 pm
Hi All,

We're told that a carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. We're asked if the carpenter were to make a similar sandbox TWICE as long, TWICE as wide, and TWICE as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox. This question can be solved by TESTing VALUES.

IF... we make the 'starting dimensions' of the sandbox (1 ft.) x (2 ft.) x (5 ft.)....
then the new dimensions (after being doubled) would be: (2 ft.) x (4 ft.) x (10 ft.)
The capacity of the new sandbox would be (2)(4)(10) = 80 cubic feet

Final Answer: D

GMAT assassins aren't born, they're made,
Rich
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by Scott@TargetTestPrep » Tue Mar 27, 2018 10:37 am
soniadiana2011 wrote:A carpenter constructed a rectangular sandbox with a
capacity of 10 cubic feet. If the carpenter were to
make a similar sandbox twice as long, twice as wide,
and twice as high as the fi rst sandbox, what would be
the capacity, in cubic feet, of the second sandbox?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100
We can let the dimensions of the original sandbox be L, W, and H. Thus we have L x W x H = 10 , and the new sandbox would have a capacity of

2L x 2W x 2H = 8 x LWH = 8 x 10 = 80 cubic feet

Answer: D

Scott Woodbury-Stewart
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