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time \ dist

by neoreaves » Tue Mar 30, 2010 9:19 am
Did it take Pei more than 2 hours to walk a distance of 10 miles along a certain trail? (1 mile= 1.6 km)
1) Pei walked this distance at an average rate of less than 6.4 km/h
2) On average, it took Pei more than 9 minutes per km to walk this distance.
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by newton9 » Tue Mar 30, 2010 9:58 am
Distance = 16 km
Time = 2 hrs.

Average speed should be 8 or greater to complete the trip.

a) Average rate is less than 6.4

So will take him greater than 2hrs.

b) 9 min -- 1 kim
So his speed is 60/9 kmph = 6.66 kmph.
Speed is less than 6.66

So either statement is sufficient and I will go with D
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by boazkhan » Wed Mar 31, 2010 12:32 pm
IMO E. What is the oA?
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by ymach3 » Mon Apr 12, 2010 4:07 am
(i) says, Total Time taken = Total dist/Avg Speed ---> 16/6.4 > 2hrs- Sufficient.

(ii) says more than 9 minutes to per Km.

Let us assume 10 minutes ---> 1 Km
160 Minutes <---- 16 Kms

Therefore time taken is 2 Hr-40 Minutes > 2 Hrs. - Sufficient.

Hence, option D.

You may shout at me if i am wrong....
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by gmatmachoman » Mon Apr 12, 2010 4:10 am
Certainly I wont shout!!! U r very much correct!!
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by ymach3 » Mon Apr 12, 2010 5:20 am
Thx Mac :)
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by Cdawg » Mon Apr 12, 2010 9:09 am
(1) maximum she could have walked is 12.8km, thus it took her certainly longer => sufficient

(2) in 2h=120min the furthest she could have walked is 120/9= 13.33km => sufficient

both statements allow to conlude that it took her longer than 2h to walk 16km

Answer: D
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