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by sana.noor » Wed Jul 31, 2013 3:17 am
Seven men and seven women have to sit around a circular table so that no 2 women are together. In how many different ways can this be done?
a.24
b.6
c.4
d.12
e.3

i dont know its answer
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by sparkles3144 » Wed Jul 31, 2013 4:55 am
14 places for 14 people

Women cannot sit next to each other. Therefore, it will be MW MW MW MW MW MW MW
Men and women will sit alternatively.

Men = 7!
Women = (7-1)! = 6!
Total = 6!*7!
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by luckypiscian » Wed Jul 31, 2013 10:59 pm
As sparkles3144 correctly mentions
"Women cannot sit next to each other. Therefore, it will be MW MW MW MW MW MW MW"

If we forget the circular table for a while
there are 7 seats for men which can be filled in 7! ways
and similarly for women that can be filled in 7! ways
7 seats for men can be chosen in 2 ways
hence total ways = 7! * 7! * 2

now arrange them on a circular table in the same sequence
n. of ways will be
7! * 7! * 2 / 14
since on a circular table ABCDEFGHIJKLMN is same as BCDEFGHIJKLMNA and 12 others (shifting 1 by 1)

= 7! * 6!
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